Question

A bullet of mass of 0.05kg is fired horizontally into a 10 kg block which is free to move with a velocity of 0.5mls after impact find the velocity with which the bullet hit the body?
show work plz..

Answer 1

It is given that :

Mass of bullet, $m_{1}$ = 0.05 Kg

Mass of block, $m_{2}$ = 10 kg

velocity after impact, v = 0.5 m/s

Let $v_{1}$  is the velocity with which the bullet is fired.

Using law of conservation of momentum :

$m_{1}v_{1}+m_{2}v_{2} = (m_{1}+m_{2})v$

$0.05 \times v_{1}+0=(0.05+10) \times 0.5\ (since, the block is at rest)$

$0.05\times v=10.05\times 0.5$

$m_{2}=100.5\ m/s$