Answer:
the height (in feet) of the cliff is 121 ft
Explanation:
A stone hit the cliff with
speed, v = 88 ft/s
Acceleration, a= 32 ft/s^2
initial speed, u = 0 ft/s
height is h.
To solve this problem we will apply the linear motion kinematic equations, Equation of motion describes change in velocity, depending on the acceleration and the distance traveled
so, writing the formula of Equation of motion:
v^2 - u^2 = 2*a*h
substituting the appropriate values,
(88)^2 - 0 = 2*32* h
h=(88)^2 / 64
h= 121 ft
hence
the height (in feet) of the cliff is 121 ft
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Answer:
1.19 hours
Explanation:
divide distance by speed. hope this helps
Answer:
Saturn's differential rotation will cause the length of a day measures to be longer by 0.4 hours
Explanation:
Differential rotation occurs due to the difference in angular velocities of an object as we move along the latitude of the or as we move into different depth of the object, indicating the observed object is in a fluid form
Saturn made almost completely of gas and has differential motion given as follows
Rotation at the equator = 10 hours 14 minutes
Rotation at high altitude = 10 hours 38 minutes
Therefore;
The differential rotation = 10 hours 38 minutes - 10 hours 14 minutes
The differential rotation = 24 minutes = 24 minutes × 1 hour/(60 minutes) = 0.4 hours
The differential rotation = 0.4 hours
Therefore, the measured day at the higher altitude will be 0.4 longer than at the equator.
Answer:
Distance, d = 778.05 m
Explanation:
Given that,
Force acting on the car, F = 981 N
Mass of the car, m = 1550 kg
Initial speed of the car, v = 25 mi/h = 11.17 m/s
We need to find the distance covered by car if the force continues to be applied to the car. Firstly, lets find the acceleration of the car:
![F=ma\\\\a=\dfrac{F}{m}\\\\a=\dfrac{981}{1550}\\\\a=0.632\ m/s^2](https://tex.z-dn.net/?f=F%3Dma%5C%5C%5C%5Ca%3D%5Cdfrac%7BF%7D%7Bm%7D%5C%5C%5C%5Ca%3D%5Cdfrac%7B981%7D%7B1550%7D%5C%5C%5C%5Ca%3D0.632%5C%20m%2Fs%5E2)
Let d is the distance covered by car. Using second equation of motion as :
![d=ut+\dfrac{1}{2}at^2\\\\d=11.17\times 35+\dfrac{1}{2}\times 0.632\times (35)^2\\\\d=778.05\ m](https://tex.z-dn.net/?f=d%3Dut%2B%5Cdfrac%7B1%7D%7B2%7Dat%5E2%5C%5C%5C%5Cd%3D11.17%5Ctimes%2035%2B%5Cdfrac%7B1%7D%7B2%7D%5Ctimes%200.632%5Ctimes%20%2835%29%5E2%5C%5C%5C%5Cd%3D778.05%5C%20m)
So, the car will cover a distance of 778.05 meters.