Answer:
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Answer:
A, C
Step-by-step explanation:
Actually, those questions require us to develop those equations to derive into trigonometrical equations so that we can unveil them or not. Doing it only two alternatives, the other ones will not result in Trigonometrical Identities.
Examining
A) True
![\frac{1-tan^{2}x}{2tanx} =\frac{1}{tan2x} \\ \frac{1-tan^{2}x}{2tanx} =\frac{1}{\frac{2tanx}{1-tan^{2}x}}\\ tan2x=\frac{1-tan^{2}x}{2tanx}](https://tex.z-dn.net/?f=%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D%20%3D%5Cfrac%7B1%7D%7Btan2x%7D%20%5C%5C%20%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D%20%3D%5Cfrac%7B1%7D%7B%5Cfrac%7B2tanx%7D%7B1-tan%5E%7B2%7Dx%7D%7D%5C%5C%20tan2x%3D%5Cfrac%7B1-tan%5E%7B2%7Dx%7D%7B2tanx%7D)
Double angle ![tan2\alpha =\frac{1 -tan^{2}\alpha }{2tan\alpha}](https://tex.z-dn.net/?f=tan2%5Calpha%20%3D%5Cfrac%7B1%20-tan%5E%7B2%7D%5Calpha%20%7D%7B2tan%5Calpha%7D)
B) False,
No further development towards a Trig Identity
C) True
Double Angle Sine Formula ![sin2\alpha =2sin\alpha *cos\alpha](https://tex.z-dn.net/?f=sin2%5Calpha%20%3D2sin%5Calpha%20%2Acos%5Calpha)
![sin(8x)=2sin(4x)cos(4x)\\2sin(4x)cos(4x)=2sin(4x)cos(4x)](https://tex.z-dn.net/?f=sin%288x%29%3D2sin%284x%29cos%284x%29%5C%5C2sin%284x%29cos%284x%29%3D2sin%284x%29cos%284x%29)
D) False No further development towards a Trig Identity
![[sin(x)-cos(x)]^{2} =1+sin(2x)\\ sin^{2} (x)-2sin(x)cos(x)+cos^{2}x=1+2sinxcosx\\ \\sin^{2} (x)+cos^{2}x=1+4sin(x)cos(x)](https://tex.z-dn.net/?f=%5Bsin%28x%29-cos%28x%29%5D%5E%7B2%7D%20%3D1%2Bsin%282x%29%5C%5C%20sin%5E%7B2%7D%20%28x%29-2sin%28x%29cos%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B2sinxcosx%5C%5C%20%5C%5Csin%5E%7B2%7D%20%28x%29%2Bcos%5E%7B2%7Dx%3D1%2B4sin%28x%29cos%28x%29)
Answer:
Option D
Y=2.6x
Step-by-step explanation:
When y=10.4 and x=4, these two can be related by the equation
10.4=4x
Making x the subject of the formula then x=10.4/4=2.6
Relating x and y then we have the equation
Y=2.6x
For example, when x is 4 then y=2.6x=2.6(4)=10.4 as given in the question. Therefore, the right option is D
Y=2.6x