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lutik1710 [3]
3 years ago
6

. Are there human health risks from exposure (or overexposure) to X-rays? If so:

Physics
2 answers:
algol [13]3 years ago
3 0
<h3>yes, there are human health risks caused by exposure to x rays</h3>
  • describe the main risk (s) ::: - may cause damage to cells in the body

                                                      - large doses may lead cells to be cancerous        

                                                      - causes mutations in the DNA

  • describe common sources of exposure ( or overexposure ) :::

           - natural background radiation   e.g. - cosmic rays

           - medical radiation   e.g. - CT scans & medical x - rays

           - man - made radiation   e.g. - airport security scanners

  • describe a technology, device, or behavior that can be used for protection, or to decrease exposure :::

          - x - ray beam filters

          - digital x - ray detectors

          - technologies reduce radiation doses in radiography &  

            mammography

<em>hope that helps !!</em>

BigorU [14]3 years ago
3 0
Do you need this in like an essay form?
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A rough surface for infrared waves may be polished for
zloy xaker [14]

Answer:

Radio Waves

Explanation:

7 0
3 years ago
A classroom has 24 fluorescent bulbs, each of which is 32 W. how much energy does it take to light the room for a minute?(unit=J
cestrela7 [59]

Answer:

Energy= 46.08KJ

Explanation:

Given that the power needed to light each bulb is 32W

We know that Power = \frac{energy}{time}

The energy needed to light one bulb=power*time

Given time = 1minute = 60 seconds

Energy = 32W*60sec=1920J

Therefore energy needed to light one bulb is 1920J

The energy needed to light 24 bulbs = 1920*24 =46080J=46.08KJ

3 0
3 years ago
Read 2 more answers
About once every 30 minutes, a geyser known as Old Faceful projects water 11.0 m straight up into the air. Use g = 9.80 m/s^2, a
Maurinko [17]

Answer:

The speed of the water is 14.68 m/s.

Explanation:

Given that,

Time = 30 minutes

Distance = 11.0 m

Pressure = 101.3 kPa

Density of water = 1000 kg/m³

We need to calculate the speed of the water

Using equation of motion

v^2=u^2+2gs

Where, u = speed of water

g = acceleration due to gravity

h = height

Put the value into the formula

0=u^2-2\times9.8\times11.0

u=\sqrt{2\times9.8\times11.0}

u=14.68\ m/s

Hence, The speed of the water is 14.68 m/s.

7 0
3 years ago
Gulls are often observed dropping clams and other shellfish from a height to the rocks below, as a means of opening the shells.
kumpel [21]

Answer:

v = 17.71 m / s

Explanation:

We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity

                v² = v₀² - 2 g (y -y₀)

                v² = 0 - 2g (y -y₀)

when it hits the stone the height is zero and part of the height of the seagull I

              v² = 2g y₀

              v = Ra (2g i)

let's calculate

              v =√ (2 9.8 16)

              v = 17.71 m / s

8 0
3 years ago
4.39 moles of gas in a box has a pressure of 2.25 atm at temperature of 385K. What is the volume of the box?
bazaltina [42]

Answer:

0.0619 m^3

Explanation

number of moles = n = 4.39 mol

pressure = P = 2.25 atm =2.25×1.01×10^5 Pa= 2.27×10^5 Pa

Molar gas constant =R = 8.31 J/(mol K)

Temperature T= 385K

volume of gas = V =?

BY GENERAL GAS LAW WE HAVE

PV = nRT

or V = nRT/P

or V = (4.39×8.31×385)/(2.27×10^5)

V = 0.0618728

V =  0.0619 m^3

5 0
4 years ago
Read 2 more answers
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