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3 years ago

. Are there human health risks from exposure (or overexposure) to X-rays? If so:

Physics

2 answers:

algol [13]3 years ago

3 0

<h3>yes, there are human health risks caused by exposure to x rays</h3>

describe the main risk (s) ::: - may cause damage to cells in the body

- large doses may lead cells to be cancerous

- causes mutations in the DNA

describe common sources of exposure ( or overexposure ) :::

- natural background radiation e.g. - cosmic rays

- medical radiation e.g. - CT scans & medical x - rays

- man - made radiation e.g. - airport security scanners

describe a technology, device, or behavior that can be used for protection, or to decrease exposure :::

- x - ray beam filters

- digital x - ray detectors

- technologies reduce radiation doses in radiography &

mammography

<em>hope that helps !!</em>

BigorU [14]3 years ago

3 0

Do you need this in like an essay form?

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a 20 kg sig is pulled by a horizontal force such that the single rope holding the sign make an angle of 21 degree with the verti

True [87]

Answer:

T= 210.15 N

F= 75.31 N

Explanation:

Let the tension in string be T newton.

According to the question

⇒T×cos21°= mg

⇒T= mg/cos21°

⇒T=20×9.81/cos21

⇒T= 210.15 N

now, the magnitude of horizontal force

F= Tsin21°

⇒F= 210.15×sin21°

=75.31 N

6 0

3 years ago

A star is known to be moving at 8.46km/s toward the earth. If you observe the spectral line to be at 5.02nm, at what wavelength

anastassius [24]

Answer:

$\lambda_x=5.019858nm$

Explanation:

From the question we are told that

Speed of star $S=8.46km/s$

Distance of spectral line $\lambda_0= 5.02nm$

Generally the equation for wavelength with respect to spectral lines is mathematically given by

$\lambda=\lambda _0 *\frac{v}{c}$

where

$\lambda_0= length\ of\ spectral\ line$

$c=The\ speed\ of\ light$

$v= speed\ of\ moving\ object$

therefore

$\lambda=5.02*10^{-9} *\frac{8.46*10^{12}}{299 792 458*10^9}$

$\lambda=1.42*10^{-4} nm$

Generally the equation for new wavelength is mathematically given as

$\lambda_x=\lambda _0-\lambda$

$\lambda_x=5.02 nm-1.42*10^{-4} nm$

$\lambda_x=5.02-1.42*10^{-4}$

Therefore

$\lambda_x=5.019858nm$

5 0

3 years ago

While traveling along a highway a driver slows from 32 m/s and comes to a stop with an acceleration of -6 m/s2. How long did it

diamong [38]

Answer: 6s

Explanation:

Vs=32m/s speed at beginning of slowing down

Vf=0m/s stop speed

a= -6 m/s² acceleration

----------------

Use equation for acceleration :

a=(Vf-Vs)/t

a*t=Vf-Vs

t=(Vf-Vs)/a

t=(0-36)/-6

t=-36/-6

t=6 s

7 0

3 years ago

Seasonal changes in water temperature tend to remain within a narrow range. This is opposed to air temperature, which tends to f

Serjik [45]

It is because of the high specific heat of water.

Specific heat is the amount of heat needed to change the temperature of unit mass of a substance by one degree.

Specific heat of water is 4.186 kJ/kg K and that of air is 1 kJ/kg K. Thus, a given amount of heat will cause more change in the temperature of air than that of water.

5 0

3 years ago

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A load of 25 kg is applied to the lower end and of a steal wire of length 25 m and thickness 3.0mm .The other end of wire is sus

Anettt [7]

Answer:

the weight of the wire + 25kg

Explanation:

6 0

3 years ago