Answer:
Charge on Moon and Earth is 5.43x10¹³ C .
Explanation:
Gravitational force is the force of attraction between any two bodies having mass while Electrostatic force is the force experienced by two charge bodies. Electrostatic force can be attractive or repulsive.
Let M and m be the mass of Earth and Moon respectively, d is the distance between Earth and Moon and q be the charge on Earth and -q be on the Moon.
Gravitational force, F₁ =
Here G is gravitational constant.
Electrostatic force, F₂ =
Here k is Coulomb constant.
According to the problem, the gravitational force between Earth and Moon is equal to the electrostatic force between them.
F₁ = F₂
=
=
Put 6.07x10⁻¹¹ N m²/kg² for G, 5.97x10²⁴ kg for M, 7.34x10²² kg for m and 9x10⁹ N m²/C² in the above equation.
= q²
q =
q = 5.43x10¹³ C
Answer:
Explanation:
m = 0.5 kg
A = 0.15 m
vmax = 1.25 m/s
vmax = ω x A
1.25 = ω x 0.15
ω = 8.33 rad/s
(a) Let the spring constant be k
k = ω² m = 8.33 x 8.33 x 0.5 = 34.7 N/m
(b) Maximum acceleration, a max = ω² A = 8.33 x 8.33 x 0.15 = 10.42 m/s^2
(c) Let f be the frequency
ω = 2 π f
8.33 = 2 x 3.14 x f
f = 1.326 Hz
(d) Total energy
E = 1 /2 m x ω² x A² = 0.5 x 0.5 x 8.33 x 8.33 x 0.15 x 0.15 = 0.39 J
Ah hah ! We can do this the easy way, or we can do it the hard way.
Whereas, in honor of, and pursuant to my natural laziness, I'm going to
do it the easy way, and not even talk about the hard way. Please fasten
your seat belt. It may be a boompy ride.
There are a few different ways to calculate the CHANGE in
an object's momentum. For this particular problem, it's
best to use this equation for "Change in momentum":
CHANGE in momentum = IMPULSE delivered to the object.
Do you remember how to calculate impulse ?
Impulse = (force exerted in the object) x (time the force lasts)
-- In the question, it says that the same force is exerted on each car,
and they all get it for 10 seconds apiece.
-- Since the force is the same on each car, and the force lasts for
the same amount of time on each car, the IMPULSE delivered to
each car is the same !
-- So the CHANGE IN MOMENTUM is the same for each car.
-- They all started out from 'rest', so each one started with zero momentum.
-- The CHANGE IN MOMENTUM is the same for each car.
-- So at the end of 10 seconds, NO CAR has the 'most momentum'.
All three cars have the SAME momentum.
Do you see why I said that this is the 'easy way' to solve it ?
The answer is 2.5 times heavier than on Earth !!
so the answer is C !!
Answer:
a)
In the constant temperature process ,change in the temperature is zero and heat addition will equal to the work done by gas.
b)
In the adiabatic process ,heat transfer is zero but the change in temperature is not zero.
c)
In the adiabatic compression process ,heat transfer is zero and in compression process work is done on the gas,that is why work done is not zero.
d)
In the constant volume process work done or work done by gas is zero ,but the heat transfer is not zero.