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hjlf
3 years ago
14

The peak of a transverse wave is called the

Physics
1 answer:
My name is Ann [436]3 years ago
5 0

Answer:

amplitude

Explanation:

the distance between 2 peaks (or 2 troughs) is called a wavelength. the deepest part of a trough or the highest part of a peak is called the amplitude.

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An AM radio station broadcasts isotropically (equally in all directions) with an average power of 3.80 kW. A receiving antenna 7
Alecsey [184]

Answer:0.1759 v

Explanation:

Intensity of wave at receiver end is

I=\frac{P_{avg}}{A}

I=\frac{3.80\times 10^3}{4\times \pi \times \left ( 4\times 1609.34\right )^2}

I=7.296\times 10^{-6} W/m^2

Amplitude of electric field at receiver end

E_{max}=\sqrt{2I\mu _0c}

Amplitude of induced emf

=E_{max}d

=\sqrt{2\times 7.29\times 10-6\times 4\pi \times 3\times 10^8}\times 0.75

=17.591\times 10^{-2}=0.1759 v

7 0
3 years ago
.<br><br> 1. True False<br> In AM waves, amplitude changes.
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That is true Step by step:
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3 years ago
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What happens to infrared radiation when it comes to contact wih a shiny suface
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If a surface looks "shiny" to you, that's because it reflects all
or most of the visible light that hits it.  That doesn't always mean
that the same surface reflects other, non-visible wavelengths of
light.  Infrared radiation may also reflect off of it, and probably
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3 years ago
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The electromagnetic spectrum consists of various ranges of electromagnetic waves. Between which of the following does the visibl
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The answer is D, it falls between the infrared and ultraviolet.
7 0
3 years ago
A 1.5-kg block slides at rest starts sliding down a snow-covered hill Point A, which has an altitude of 10 m. There is no fricti
damaskus [11]

Answer:

the speed of the block when it reaches point B is 14 m/s

Explanation:

Given that:

mass of the block slides = 1.5 - kg

height = 10 m

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coefficient of kinetic friction = 0.15

In order to determine the speed of the block when it reaches point B.

We consider the equation for the energy conservation in the system which can be represented by:

\dfrac{1}{2}mv^2=mgh

\dfrac{1}{2}v^2=gh

v^2=2 \times g \times   h

v^2=2 \times 9.8 \times   10

v=\sqrt{2 \times 9.8 \times   10

v=\sqrt{196

v = 14 m/s

Thus; the speed of the block when it reaches point B is 14 m/s

7 0
3 years ago
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