P = mv
v = p/m
v = (25 kg m/s) / (12.0 kg)
v = 2.08 m/s
v = 2.1 m/s
Answer:
The beat frequency is 0.0019 MHz.
Explanation:
Given that,
Velocity = 0.32 m/s
Frequency = 4.40 MHz
Speed of wave = 1540 m/s
We need to calculate the frequency
Case (I),
Observer is moving away from the source
Using Doppler's effect
Where, v' = speed of observer
Put the value into the formula
Case (II),
Cell is as the source of sound of frequency f' and it moving away from the observer.
Using formula of frequency
We need to calculate the beat frequency
Hence, The beat frequency is 0.0019 MHz.
Answer:
E=7453.99 V/m
Explanation:
The electric field on the charged is given by
E= Kqx/(r^2 +x^2)^3/2
Where;
K= constant of Coulomb's law
q= magnitude of charge= 30.0×10^-9 C
r= radius of the rings= 5 cm or 0.05m
x= distance between the rings = 18cm = 0.18 m
Substituting values;
E= 9.0×10^9 × 30.0×10^-9 × 0.18 / [(0.05^2 + (0.18)^2]^3/2
E= 48.6/(2.5×10^-3 + 0.0324)^3/2
E= 48.6/(0.0025 + 0.0324)^3/2
E= 48.6/6.52×10^-3
E=7453.99 V/m
Answer:
Gravitational force, F = 1054.65 N
Explanation:
Given,
The accelerating speed, a = 15 m/s²
The mass of your body, m = 155 lbs
= 70.31 Kg
The gravitational force acting in a body is given by the relation
F = m x g
Where g is the acceleration due to gravity of the in which the velocity of the body changes its speed at a constant rate.
∴ a = g
Substituting the values in the above equation
F = 70.31 x 15
= 1054.65 N
Hence, the gravitational force acting on you, F = 1054.65 N
Answer:
The strength of the magnetic field is 0.08 mT
Explanation:
Given:
Length of rod m
Velocity of rod
Induced emf V
According to the faraday's law
We know that the induced emf of rod is given by,
Where magnetic field
For finding the magnetic field,
mT
Therefore, the strength of the magnetic field is 0.08 mT