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Tju [1.3M]
2 years ago
10

Which model best represents a pattern

Physics
2 answers:
Svetach [21]2 years ago
4 0

Answer:

A

Explanation:

olasank [31]2 years ago
3 0
Where is the options ?
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You hang a heavy ball with a mass of 10 kg from a gold wire 2.6 m long that is 1.6 mm in diameter. You measure the stretch of th
PolarNik [594]

<u>Answer:</u> The Young's modulus for the wire is 6.378\times 10^{10}N/m^2

<u>Explanation:</u>

Young's Modulus is defined as the ratio of stress acting on a substance to the amount of strain produced.

The equation representing Young's Modulus is:

Y=\frac{F/A}{\Delta l/l}=\frac{Fl}{A\Delta l}

where,

Y = Young's Modulus

F = force exerted by the weight  = m\times g

m = mass of the ball = 10 kg

g = acceleration due to gravity = 9.81m/s^2

l = length of wire  = 2.6 m

A = area of cross section  = \pi r^2

r = radius of the wire = \frac{d}{2}=\frac{1.6mm}{2}=0.8mm=8\times 10^{-4}m      (Conversion factor:  1 m = 1000 mm)

\Delta l = change in length  = 1.99 mm = 1.99\times 10^{-3}m

Putting values in above equation, we get:

Y=\frac{10\times 9.81\times 2.6}{(3.14\times (8\times 10^{-4})^2)\times 1.99\times 10^{-3}}\\\\Y=6.378\times 10^{10}N/m^2

Hence, the Young's modulus for the wire is 6.378\times 10^{10}N/m^2

3 0
3 years ago
The answer can't be D because I got it wrong when I took my test so it has to be A,B,or C
Cerrena [4.2K]
To what question please put the question ill be glad to help
5 0
3 years ago
Does anyone know these four?! I really need help and fast pls
Mama L [17]

Evidence: Data gathered

Experiment: Looking through a telescope

Observations: Testing what happens

Reasoning: Thinking a problem through

I believe that these should be correct.

Hoping you pass!

3 0
2 years ago
Indicate whether each source is reliable or unreliable
Alex73 [517]

Answer:

1.reliable

2.unreliable

3.unreliable

4.reliable

5.reliable

Explanation: edg 2020

6 0
3 years ago
Read 2 more answers
A mass of 5 kg is moving at 5 m/s when it collides with another mass of 2 kg moving in the same direction at 2 m/s. After the co
Paul [167]

Answer:

4.14 m/s

Explanation:

m¹u¹+m²u²=(m¹+m²)v

5(5)+2(2)=(5+2)v

25+4=7v

29=7v

29/7=v

v=4.14 m/s

6 0
3 years ago
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