All categories

3 years ago

How many moles of O2 are needed to react completely with 35.0 mol of 10 points

Chemistry

1 answer:

yKpoI14uk [10]3 years ago

4 0

D.10.0 mol is the correct

You might be interested in

What is the position of the element ammonia in periodic table?

Rashid [163]

Ammonia isn't an element, it's a compound made by mixing the elements Nitrogen and Hydrogen in the Haber process. Therefore, it isn't on the periodic table

8 0

3 years ago

Read 2 more answers

What is the final volume of 20L of gas at 300K that is heated to 600K at constant pressure?

maxonik [38]

Answer:

Explanation:

6 0

3 years ago

A 0.25-mol sample of a weak acid with an unknown Pka was combined with 10.0-mL of 3.00 M KOH, and the resulting solution was dil

Masteriza [31]

Answer : The value of $pK_a$ of the weak acid is, 4.72

Explanation :

First we have to calculate the moles of KOH.

$\text{Moles of }KOH=\text{Concentration of }KOH\times \text{Volume of solution}$

$\text{Moles of }KOH=3.00M\times 10.0mL=30mmol=0.03mol$

Now we have to calculate the value of $pK_a$ of the weak acid.

The equilibrium chemical reaction is:

$HA+KOH\rightleftharpoons HK+H_2O$

Initial moles 0.25 0.03 0

At eqm. (0.25-0.03) 0.03 0.03

= 0.22

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[HK]}{[HA]}$

Now put all the given values in this expression, we get:

$3.85=pK_a+\log (\frac{0.03}{0.22})$

$pK_a=4.72$

Therefore, the value of $pK_a$ of the weak acid is, 4.72

7 0

3 years ago

How to find the valency of iron

anastassius [24]

When iron loses the 2 4s electrons, it attains a valency of +2. Sometimes, iron will also lose one of the paired electrons from 3d orbital, leaving the entire 3d orbital filled with unpaired electrons (which provides a more stable configuration). In this case, its valency will be +3.

3 0

3 years ago

How many grams are in 3.45 moles of CaCl2

Firdavs [7]

Answer:

Explanation:

First we find the Molecular weight of CaCl2

looking at the periodic table the MW of Ca is 40.078 and Cl is 35.453 and the ratio of ca to cl is 1:2 so we multiply cl by 2 which is 35.453*2=70.906

we add them together: 40.078 + 70.906 = 110.984 g/mol

now:

$\frac{110.984 grams}{mol}$ * 3.45 mol

the mol cancels out and we left with 3.45 * 110.984 grams = 382.89 grams

6 0

3 years ago