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3 years ago

One major advantage of push/pull steering from the low-hand position is

1 answer:

6 0

One major advantage of push/pull steering from the low-hand position is enhanced vehicle control because the arms stay close to the body and helps to maintain a more stable vertical body position.

The hands are always placed on the steering and if the person encounters any unexpected situation, the person can make an instantaneous counter maneuver. It is designed in such a way that the arms are not covering the airbag.It stops sudden input of steering to avoid any under-steer or over-steer situation. Thus push/pull steering gives enhanced control over the vehicle.

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A 10kg box is sliding at 50m/s. Find the momentum

MAXImum [283]

Answer:

The momentum of the ball is 500 kg·m/s

Explanation:

The momentum is given by Mass × Velocity

The given parameters are;

The mass of the box = 10 kg

The velocity by which the box is sliding = 50 m/s

Therefore, the momentum of the ball is given as follows;

The momentum of the ball = 10 kg × 50 m/s = 500 kg·m/s

The momentum of the ball = 500 kg·m/s

5 0

3 years ago

Please Please Please Can Help Me On This Question!!!!! I Give Thanks!!!! Please Do 1-4!!!! Please Please Help Nobody Is Helping

DENIUS [597]

Not sure if this is what you’re looking for. Let me know if I can clarify anything.

6 0

3 years ago

Arrow_forward

garri49 [273]

Explanation:

(a) Hooke's law:

F = kx

7.50 N = k (0.0300 m)

k = 250 N/m

(b) Angular frequency:

ω = √(k/m)

ω = √((250 N/m) / (0.500 kg))

ω = 22.4 rad/s

Frequency:

f = ω / (2π)

f = 3.56 cycles/s

Period:

T = 1/f

T = 0.281 s

EE = ½ (250 N/m) (0.0500 m)²

EE = 0.313 J

(d) A = 0.0500 m

(e) vmax = Aω

vmax = (0.0500 m) (22.4 rad/s)

vmax = 1.12 m/s

amax = Aω²

amax = (0.0500 m) (22.4 rad/s)²

amax = 25.0 m/s²

(f) x = A cos(ωt)

x = (0.0500 m) cos(22.4 rad/s × 0.500 s)

x = 0.00919 m

(g) v = dx/dt = -Aω sin(ωt)

v = -(0.0500 m) (22.4 rad/s) sin(22.4 rad/s × 0.500 s)

v = -1.10 m/s

a = dv/dt = -Aω² cos(ωt)

a = -(0.0500 m) (22.4 rad/s)² cos(22.4 rad/s × 0.500 s)

a = -4.59 m/s²

3 0

3 years ago

A wave has a speed of 50 m/s and a frequency of 100 Hz. Calculate its wavelength.

Allisa [31]

Answer:

1/2m or 0.5m

Explanation:

The formula to find the speed of a wave is given by:

V = frequency x wavelength

To find the wavelength, make the wavelength the subject of the formula

Therefore, wavelength = velocity ÷ frequency

8 0

3 years ago

42,43 and 44 please

Mariana [72]

42) The sailboat travels east with velocity $v_e=30 mph$ , while the current moves south with speed $v_s=30 mph$ . Since the two velocities are perpendicular to each other, he resultant velocity will be given by the Pytagorean theorem:
$v= \sqrt{v_e^2+v_s^2}= \sqrt{(30)^2+(30)^2}=42 mph$
and the direction is in between the two original directions, therefore south-east. So, the correct answer is
D) 42 mph southeast

43) Since the light moves by uniform motion, we can calculate the distance corresponding to one light year by using the basic relationship between velocity, space and time. In fact, we know the velocity:
$v=300,000,000 m/s=3 \cdot 10^8 m/s$
and the time is one year, corresponding to:
$t=32,000,000 s=3.2 \cdot 10^7 s$
therefore, the distance corresponding to one light year is:
$S=vt=(3\cdot 10^8 m/s)(3.2 \cdot 10^7 s)=9.6 \cdot 10^{15}m$
Therefore, the correct answer is D.

44) For the purpose of the problem, we can assume that the light travels instantaneously from the flash to us (because the distances involved are very small), so the time between the flash and the thunder corresponds to the time it took for the sound to travel to us.
The speed of sound is
$v=1100 ft/s=750 mph=335 m/s$
And since the time between the flash and the thunder is t=3 s, the distance is
$S=vt=(335 m/s)(3 s)=1005 m=0.62 miles$
Therefore, the correct answer is A) 3/5 mile.

6 0

3 years ago