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Illusion [34]
4 years ago
9

In a vacuum, which has a greater acceleration while in free fall: a7 kg bowling ball or a 0.007 kg feather?

Physics
1 answer:
Klio2033 [76]4 years ago
6 0

Answer:the will have the same acceleration

Explanation:according to fállelos theory they land at the same time

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g Design an experiment you can use to determine the mass of the metal cylinder. When you explain your experiment, be sure to men
kumpel [21]

Answer:

m = \frac{k}{g} x,

graph of x vs m

Explanation:

For this exercise, the simplest way to determine the mass of the cylinder is to take a spring and hang the mass, measure how much the spring has stretched and calculate the mass, using the translational equilibrium equation

              F_e -W = 0

              k x = m g

              m = \frac{k}{g} x

We are assuming that you know the constant k of the spring, if it is not known you must carry out a previous step, calibrate the spring, for this a series of known masses are taken and hung by measuring the elongation (x) from the equilibrium position, with these data a graph of x vs m is made to serve as a spring calibration.

  In the latter case, the elongation measured with the cylinder is found on the graph and the corresponding ordinate is the mass

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3 years ago
6. For a cell to produce a current, the
Reil [10]

Answer:

for a cell to produce a current the cell electrodes of the cell must have a potential difference option A is the correct answer

6 0
2 years ago
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1. Which area should one seek if caught outside in a thunderstorm?
Oliga [24]

Answer:

1. sturdy shelter

2. i am preaty shure all of them

Explanation:

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4 years ago
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Help me pleaseeee I will give you 42 points!<br> (I am dumb so that’s why)
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Search each one of them up on GOOGLE it’s easier trust me
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4 years ago
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A 22-g bullet traveling 265 m/s penetrates a 1.9 kg block of wood and emerges going 125 m/s .
Usimov [2.4K]

The body moves at a velocity of 1.62m/s after the bullet emerges.

<h3>Given:</h3>

Mass of bullet, m_1 = 22g

                               = 0.022 kg

Mass of the block, m_2 = 1.9 kg

Velocity of bullet , v_1 = 265 m/s

v_2 = 0

According to the law of collision which states that the momentum of the body before the collision is equal to the momentum of the body after the collision.

After penetration;

v^{'}_1 =125 m/s

v^{'}_2=?

The formula for calculating the collision of a body is expressed as:

p = mv

m is the mass of the body

v is the velocity of the body

∴ Momentum before = Momentum after

Substitute the given parameters into the formula as shown:

   m_1v_1+ m_2v_2 = m_1v^{'}_1+ m_2v^{'}_2\\0.022* 265 + 0 = 0.022*125+1.9*v^{'}_2\\5.83 = 1.9 v^{'}_2\\v^{'}_2 = 1.62 m/s

Therefore, It moves with a velocity of 1.62 m/s.

Learn more about momentum here:

brainly.com/question/25121535

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2 years ago
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