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Olenka [21]
3 years ago
9

What controls flowering in many plants?

Chemistry
1 answer:
katrin2010 [14]3 years ago
3 0

Answer:

All flowering is regulated by the integration of environmental cues into an internal sequence of processes. These processes regulate the ability of plant organs to produce and respond to an array of signals. The numerous regulatory switches permit precise control over the time of flowering.

Explanation:

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How do I create an atom with a mass of 3 and a neutral charge?
kupik [55]

Answer:

a lithium atom (Z=3, A=7 AMU) contains three protons (found from Z), three electrons (as the number of protons is equal to the number of electrons in an atom), and four neutrons (7 – 3 = 4).

Explanation:

6 0
2 years ago
Why are the bacterial endospores placed on the paper strip and not directly in the fermentation broth?
Artyom0805 [142]
The bacterial endospores are microorganisms formed due to nutrient deprivation. These are placed first on a paper strip and not directly in the fermentation broth because these microorganisms are very resistance, thus, they need to adjust to the environment first before being acclimated to it. 
6 0
4 years ago
What forms white light?
leva [86]

Answer:

Combination of all the wavelengths of visible light.

Explanation:

Hope it helps you :))))

Have a good day

6 0
2 years ago
How many cubic cm^3 would be present in a space that is 5.00 in x 4.00 in x 7.00 in?​
Sliva [168]
Okay so just add all of them up the fine the x and the y and d the times that by the size of yiurn four head
5 0
3 years ago
What volume of a 0.3300-m solution of sodium hydroxide would be required to titrate 15.00 ml of 0.1500 m oxalic acid? c2 o4 h2(a
shtirl [24]

Answer : 13.64 mL


Explanation : The reaction requires 13.64 mL of NaOH 

From the reaction we know that oxalic acid requires two moles of NaOH so we have to calculate the number of moles of both.

0.150 L X 0.1500 moles/L = 2.25 X 10^{-3}

So the moles of NaOH will be 2 X (2.25 X 10^{-3}) =  4.5 X 10^{-3}

Now, we know the concentration of NaOH as 0.330 M

4.5 X 10^{-3} moles / 0.330 moles/L = 0.01364 L or 13.64 mL

So, the volume of NaOH needed to neutralize oxalic acid will be 13.64 mL

8 0
3 years ago
Read 2 more answers
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