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masha68 [24]
3 years ago
8

A population of 400 beetles grows by 5% each week. How can the beetle population be determined after a number of weeks, w?

Mathematics
1 answer:
patriot [66]3 years ago
7 0
*5% in decimal form is 0.05.

After one week we have:
N=400*1.05 beetles

After two weeks we have:
N=(400*1.05)*1.05 beetles

After three weeks we have:
N=((400*1.05)*1.05)*1.05 beetles

We can write this as:
Week 1:
N=400* 1.05^{1}
Week 2:
N=400* 1.05^{2}
Week 3:
N=400* 1.05^{3}

From this we can make conclusion that formula for number of beetles after w weeks is given by:
N=400* 1.05^{w}
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the slope of a line passing through h (-2, 5) is -3/4. Which ordered pair represents a point on this line? ​
rosijanka [135]

Answer:

A

Step-by-step explanation:

Calculate the slope of the given points with the point (- 2,  5 )

If the slope is - \frac{3}{4} then the point is on the line

Calculate slope m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (6, - 1)

m = \frac{-1-5}{6+2} = \frac{-6}{8} = - \frac{3}{4} ← point (6, - 1) is on the line

Repeat with (x₁, y₁ ) = (- 2, 5 ) and (x₂, y₂ ) = (2, 8)

m = \frac{8-5}{2+2} = \frac{3}{4} ← point (2, 8) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (- 5, 1)

m = \frac{1-5}{-5+2} = \frac{-4}{-3} = \frac{4}{3} ← point (- 5, 1) is not on the line

Repeat with (x₁, y₁ ) = (- 2, 5) and (x₂, y₂ ) = (1, 1)

m = \frac{1-5}{1+2} = - \frac{4}{3} ← point (1, 1) is not on the line

Thus the point on the line is (6, - 1 ) → A

4 0
3 years ago
Determine if the sides are greater than (>), less than (<), or equal (=) to each other.
DochEvi [55]

In ∆BCE

\\ \sf\longmapsto

\\ \sf\longmapsto

\\ \sf\longmapsto

Opposite side to <E=BC

Opposite side to <B=EC

  • <E=<B

\\ \sf\longmapsto BC=EC

4 0
3 years ago
PLEASE HELP MEE
KATRIN_1 [288]

Answer:

I'm only going to find the value of each variable

Step-by-step explanation:

V,Z,W,Y=39

X=94

Sorry, I didn't know how to explain the relevant angle relationships. '-' :(

8 0
3 years ago
Helen's house is located on a rectangular lot that is1 1-8 miles by 9/10 mile.Estimate the distance around the lot
klemol [59]

Answer: The distance around the lot is given by

4\frac{1}{20}\ miles

Step-by-step explanation:

Since we have given that

Length of rectangular lot is given by

1\frac{1}{8}\\\\=\frac{9}{8}\ miles

Width of rectangular lot is given by

\frac{9}{10}\ mile

We need to find the distance around the lot.

As we know the formula for "Perimeter of rectangle":

Perimeter=2(Length+Width)\\\\Perimeter=2(\frac{9}{8}+\frac{9}{10})\\\\Perimeter=2(\frac{45+36}{40})\\\\Perimeter=2\times \frac{81}{40}\\\\Perimeter=\frac{81}{20}\\\\Perimeter=4\frac{1}{20}\ miles

Hence, the distance around the lot is given by

4\frac{1}{20}\ miles


3 0
3 years ago
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Svetllana [295]

Answer:


Step-by-step explanation:


8 0
3 years ago
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