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3 years ago

12

A snail can move app approximately 0.30 inches per minute. How many meters can the snail cover in 15 minutes

2 answers:

Blababa [14]3 years ago

8 0

Answer:

4.5 because just do the math and its 4.5

Phoenix [80]3 years ago

3 0

4.5 i’m pretty sure sorry if i’m wrong

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What conditions are typcial of the soil the deeper we dig into it?

Tems11 [23]

When we first dig into soil, it's nice and soft.( Depending on what soil it is; usually topsoil)

But when we go deeper into it, there are rocks and the soil is harder. There is bedrock at the bottom, subsoil in the middle, and topsoil at the top, which is where we walk.

8 0

3 years ago

Consider two antennas separated by 9.00 m that radiate in phase at 120 MHz, as described in Exercise 35.3. A receiver placed 150

alexgriva [62]

Answer:

$\phi=4.52 rad$

Explanation:

From the question we are told that

Distance b/e antenna's $d=9.00m$

Frequency of antenna Radiation $F_r=120 MHz \approx 120*10^6Hz$

Distance from receiver $d_r=150m$

Intensity of Receiver $i= 10$

Distance difference of the receiver b/w antenna's $(r^2-r^1)=1.8m$

Generally the equation for Phase difference $\phi$ is mathematically given by

$\phi=\frac{2\pi}{\frac{c}{f_r}} *(r^2-r^1)$

$\phi=\frac{2*\pi}{\frac{3*10^{8}}{120*10^6}} *1.8$

$\phi=\frac{4\pi}{5} *1.8$

<h3> $\phi=4.52 rad$ </h3>

Therefore phase difference f between the two radio waves produced by this path difference is given as

$\phi=4.52 rad$

7 0

3 years ago

I need a short answer ?

mars1129 [50]

Answer:

Explanation:

7a) t = d/v = 100/45cos14.5 = 2.29533...= 2.30 s

7b) h = ½(9.81)(2.29533/2)² = 6.46056... = 6.45 m

or

h = (45sin14.5)² / (2(9.81)) = 6.47 m

which rounds to the same 6.5 m when limiting to the two significant digits of the initial velocity.

7 0

2 years ago

Calculate the magnitude of the linear momentum for the following cases. (a) a proton with mass 1.67 10-27 kg, moving with a spee

abruzzese [7]

Answer:

<h2>8.0995×10^-21 kgms^-1</h2>

Explanation:

Mass of proton :

$m_P=1.67\times 10^-^2^7\:kg\\$

Speed of Proton:

$v_P=4.85\times 10^6$

Linear Momentum of a particle having mass (m) and velocity (v) :

$-> p =m->v\:\:\: (1)$

Magnitude of momentum :

$p=mv\:\:\: (2)$

Frome equation (2), magnitude of linear momentum of the proton :

$p_P=m_P\:v_P\\\\p_P=1.67\times 10^-^2^7 \:kg\times4.85\times 10^6\:ms^-^1\\\\p_P= 8.0995\times 10^-^2^1\:kgms^-^1$

7 0

3 years ago

Andre is playing air hockey with Alexa and shoots his puck across the essentially frictionless surface to score a goal. What fre

DaniilM [7]

Answer:

The answer is C because there is no friction there will be no friction force only applied and since its on ice you have to account for gravity

Explanation:

3 0

3 years ago