Calculate the mass in grams in nine molecules of CH3COOH? Please show how you got your answer.

1 answer:

7 0

M CH₃COOH: 12u×2 + 1u×4 + 16u×2 = 60u

m 9CH₃COOH: 60u×9 = 540u

(1u ≈ 1,66·10⁻²⁴g)
-----------------------------
1u ------- 1,66·10⁻²⁴g
540u ---- X
X = 540×1,66·10⁻²⁴g
X = 896,4·10⁻²⁴g

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