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romanna [79]
3 years ago
11

A slow chemical reaction will have...

Chemistry
1 answer:
yawa3891 [41]3 years ago
5 0

Answer:

Ay high concentration of reactants

Explanation:

To slow down a reaction, you need to do the opposite. Factors that can affect rates of reactions include surface area, temperature, concentration, and the presence of catalysts and inhibitors. ... Concentration - another way to increase the rate of a chemical reaction is to increase the concentration of the reactants.

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Give the o.N. Of each of the elements magnesium and oxygen in the reactants and in the products 2Mg + O2=2MgO
vlada-n [284]

Answer:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Explanation:

Hello there!

In this case, according to the rules for the oxidation states in chemical reactions, it is possible to realize that lone elements have 0 and since magnesium is in group 2A, it forms the cation Mg⁺² as it loses electrons and oxygen is in group 6A so it forms the anion O⁻²; therefore resulting oxidation numbers are:

2Mg^0 + O_2^0\rightarrow2Mg^{2+}O^{2-}

Best regards!

4 0
2 years ago
A 1.800-g sample of solid phenol (C6H5OH(s)) was burned in a bomb calorimeter whose total heat capacity is 11.66 kJ/?C. The temp
vichka [17]

Answer:

The balanced chemical equation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat of combustion per gram of phenol is 32.454 kJ/g

Heat of combustion per gram of phenol is 3,050 kJ/mol

Explanation:

C_6H_5OH(s)+7O_2(g)\rightarrow 6CO_2(g)+3H_2O(g)

Heat capacity of calorimeter = C = 11.66 kJ/°C

Initial temperature of the calorimeter = T_1= 21.36^oC

Final temperature of the calorimeter = T_2= 26.37^oC

Heat absorbed by calorimeter = Q

Q=C\times \Delta T

Heat released during reaction = Q'

Q' = -Q ( law of conservation of energy)

Energy released on combustion of 1.800 grams of phenol = Q' = -(58.4166 kJ)

Heat of combustion per gram of phenol:

\frac{Q'}{1.800 g}=\frac{-58.4166 kJ}{1.800 g}=32.454 kJ/g

Molar mass of phenol = 94 g/mol

Heat of combustion per gram of phenol:

\frac{Q'}{\frac{1.800 g}{94 g/mol}}=\frac{-58.4166 kJ\times 94 g/mol}{1.800 g}=3,050 kJ/mol

3 0
3 years ago
What are weather balloons? (3 points)
WARRIOR [948]
C! objects that carry instruments into the stratosphere to measure atmospheric conditions
4 0
3 years ago
Read 2 more answers
Could someone help me balance this chemical equation please
Softa [21]
Balanced equation:
Ca(OH)2+H2SO4=CaSO4+2 H20<span />
4 0
3 years ago
What is the percent of oxygen by mass in C2H402
Rom4ik [11]

Answer:

53.3 %.

Explanation: C2H4O2. = 2 * 12.011 + 4 * 1.008 + 2 * 15.999. = 60.052.

6 0
2 years ago
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