Answer:
4 moles of NH3 will be produced
Explanation:
The reaction expression is given as:
N₂ + 3H₂ → 2NH₃
We have to check that the equation of the reaction is balanced.
Then;
if 2 mole of N₂ reacts;
1 mole of N₂ will react with 3 mole of H₂ to produce 2 mole of NH₃
2 mole of N₂ will react with (2x3)mole of H₂ to produce (2x2)mole of NH₃
6mole of H₂ to produce 4 mole of NH₃
Answer:
The answer to your question is B. metallic
Explanation:
Covalent bonding is a bond between two nonmetals and the difference in electronegativity is between 0 and 1.7. Sodium could not have this kind of bond because is a metal.
Ionic bonding is a bond between a metal and a nonmetal and the difference of electronegativity is higher than 1.7. Sodium can have this kind of bond it is necessary one nonmetal.
Metallic, sodium has a metallic bond because this bond is characteristic of metals.
Energy released from changing the phase of a substance from the gas phase to liquid phase can be calculated by using the specific latent heat of vaporization. The heat of fusion of water at 0 degrees Celsius is 40.7 kJ/mol. Calculation are as follows:<span> </span>
Energy = 27.9 g (1 mol / 18.02 g) x 40.7 kJ/mol
Energy = 63.09 kJ
Answer: 0.745 g of 
will be produced from 1.08 g of sodium sulfate
Explanation:
To calculate the moles :
is the limiting reagent as it limits the formation of product and 
is the excess reagent.
According to stoichiometry :
3 moles of produce = 3 moles of
Thus 0.0076 moles of will require=
of
Mass of 
Thus 0.745 g of will be produced from 1.08 g of sodium sulfate
We can store the copper sulphate solution in alumiun container, if cover on alumiun is present.
<h3>Can you store cuso4 in an aluminum container?</h3>
Aluminium is more reactive than copper so the Aluminium will displace copper sulphate from its solution by reacting with it but if there is cover on the aluminium then the alumium can't react with copper.
So we can store the copper sulphate solution in alumiun container.
Learn more about container here: brainly.com/question/11459708
