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3 years ago

(15 points) (Asap!!)In what two ways can you increase the elastic potential energy of a spring?

2 answers:

5 0

Hello There

Answers: The elastic potential energy can be increased by: 

1) Getting a spring with a higher spring constant

2) Increasing the length at which the spring is compressed.

Reasons: Getting a stronger spring makes it stronger which equals more energy. While increasing the compression on the spring, increases the stored energy which makes it more powerful when its released

I hope this helps
-Chris

Fittoniya [83]3 years ago

3 0

Getting a stiffer spring (one with a higher spring constant) and increasing the length at which the spring is compressed. 
Hope this helps.

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If you were trying to describe the difference between power and work you could say:

avanturin [10]

Power is the energy transferred or "WORK DONE" in one second

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3 years ago

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Hanging from a horizontal beam are nine simple pendulums of the following lengths:

LenaWriter [7]

Answer:

Options d and e

Explanation:

The pendulum which will be set in motion are those which their natural frequency is equal to the frequency of oscillation of the beam.

We can get the length of the pendulums likely to oscillate with the formula;

$L =\frac{g}{w^{2} }$

where g=9.8m/s

ω= 2rad/s to 4rad/sec

when ω= 2rad/sec

$L= \frac{9.8}{2^{2} }$

L = 2.45m

when ω= 4rad/sec

$L=\frac{9.8}{4^{2} }$

L = 9.8/16

L=0.6125m

L is between 0.6125m and 2.45m.

This means only pendulum lengths in this range will oscillate.Therefore pendulums with length 0.8m and 1.2m will be strongly set in motion.

Have a great day ahead

8 0

3 years ago

A person in the back of a pick-up moving at 20 m/s relative to the Earth, throws a baseball with a speed of 15 m/s in a directio

Bumek [7]

Answer:

This is known as a Galilean transformation where

V' = V - U

Where the primed frame is the Earth frame and the unprimed frame is the frame moving with respect to the moving frame

V - speed of object in the unprimed frame

U - speed of primed frame with respect to the unprimed frame

Here we have:

V = -15 m/s speed of ball in the moving frame (the truck)

U = -20 m/s speed of primed (rest) frame with respect to moving frame

So V' = -15 - (-20) = 5 m/s

It may help if you draw a vector representing the moving frame and then add

a vector representing the speed of the ball in the moving frame.

3 0

3 years ago

You toss a walnut at a speed of 15.0 m/s at an angle of 50.0∘ above the horizontal. The launch point is on the roof of a buildin

kaheart [24]

Answer:

a.3.51s

b.33.8m

c. 9.64,-22.9

Explanation:

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2 years ago

6. A 50 N block is raised 2 m. If the net work done on the block is 50 J, what is the applied force on the block?

geniusboy [140]

Answer:

F = 75[J]

Explanation:

We know that work is defined as the product of force by distance.

In this way we have two forces, the weight of the block down, and the force that bring about the block to rise.

$W = -(F_{weight*d})+(F_{upward}*d)$

where:

W = work = 50 [J]

d = distance = 2 [m]

Fweight = 50 [N]

Fupward [N]

Now replacing:

$50=-(50*2)+(F_{upward}*2)\\50+100=F_{upward}*2\\F_{upward}=150/2\\F_{upward}=75[J]$

5 0

3 years ago