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Vesna [10]
3 years ago
14

Scientists are trying to control the Maillard reaction by?​

Chemistry
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

Intervention of Maillard reactions by the addition of natural and synthetic chemical compounds has previously been directed toward removing one of the reactants (the amino groups or the reducing sugars) or adding sulfur-containing compounds, such as sulfur dioxide or N-acetyl cysteine, which inhibit the reactions

Explanation:

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Smartphone batteries contain a casing that surrounds it that is made up out of aluminium. What would best describe the propertie
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it contains the electricity of the battery

Explanation:

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In caves, dripping groundwater containing calcium bicarbonate can form stalactites and stalagmites. When the water is exposed to
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This is a chemical change because there is a new substance that was created and the new chemical can cause other chemical reaction to happen compared to the 1st state of chemical that was in the cave. Because the cave water was exposed to another environment, the calcium bicarbonate, which is also known as salt. When the cave's groundwater was exposed to a different environment the atom in the cave water rearranged and crystallized.  
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Classify each process as either physical or a chemical change.
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Answer:

I think they are all correct

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A student shines a flashlight on a mirror.
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a

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1. A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C. If the
Maurinko [17]

Answer:

Mass of aluminium in sample = 3.591 g ≅ 3.6 grams

Explanation:

Given that,  A sample of aluminum absorbs 50.1 J of heat, upon which the temperature of the sample increases from 20.0°C to 35.5°C.

the specific heat of aluminum is 0.900 J/g- °C

The relation between heat absorbed and change in temperature is given by,   Q = msΔT.

where Q = heat absorbed

            m = mass of the substance

            s = specific heat of substance

          ΔT  = change in temperature

Now, in our case, Q = 50.1 J ; s = 0.900 J/g- °C; ΔT= 35.5-20 = 15.5°C

⇒ m =  \frac{Q}{s(T_{2} -T_{1}) }

⇒ m = \frac{50.1}{0.900(15.5)} = 3.591 g ≅ 3.6 g

⇒ m ≅ 3.6 g

5 0
3 years ago
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