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2 years ago

Scientists are trying to control the Maillard reaction by?

Chemistry

1 answer:

dimaraw [331]2 years ago

5 0

Answer:

Intervention of Maillard reactions by the addition of natural and synthetic chemical compounds has previously been directed toward removing one of the reactants (the amino groups or the reducing sugars) or adding sulfur-containing compounds, such as sulfur dioxide or N-acetyl cysteine, which inhibit the reactions

Explanation:

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Integrated Problem 01.69 With current spectroscopic techniques, chemists are generally able to determine the structure of an unk

Gnesinka [82]

a or c becuse it means you should answer it very wiseley

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2 years ago

The instructions for the experiment direct you to prepare 30 mL of 1.5 M HCl solution. In the chemical closet, you locate an 18M

MAVERICK [17]

The volume of the 18M HCl needed to make the solution will be 2.5 mL.

<h3>Dilution</h3>

According to the dilution principle, the number of moles of solutes in a solution before and after dilution must remain the same.

Since, mole = molarity x volume

Thus, molarity x volume before dilution = molarity x volume after dilution.

Mathematically, the equation is written as: m1v1 = m2v2

In this case, m1 = 18 M, m2 = 1.5 M, and v2 = 30 mL.

What we are looking for is v1, the amount of the stock HCl needed for dilution.

v1 = m2v2/m1 = 1.5 x 30/18 = 2.5 mL.

Thus, 2.5 mL of the stock HCl would be needed.

More on dilution can be found here: brainly.com/question/21323871

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2 years ago

The burr oak trees in the forest are which of these?

hammer [34]

Answer:

I think It is an organism

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2 years ago

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Why is peer review important when publishing experimental results?

erastovalidia [21]

When publishing experimental results, it is always advisable to have your peer review those results. This peer can confirm the results that you got and thus they will be more reliable.

Also, you will be sure that what what you are publishing is correctly presented as it is always good to have a fresh eya to double-check what is written.

7 0

3 years ago

At a certain temperature, the K p Kp for the decomposition of H 2 S H2S is 0.834 . 0.834. H 2 S ( g ) − ⇀ ↽ − H 2 ( g ) + S ( g

stira [4]

Answer:

Total pressure at equilibrium is 0.2798atm.

Explanation:

For the reaction:

H₂S(g) ⇄ H₂(g) + S(g)

Kp is defined as:

$Kp = \frac{P_{H_{2}}*P_S}{P_{H_{2}S}} = 0.834$

If initial pressure of H₂S is 0.150 atm, equilibrium pressures are:

H₂S(g): 0.150atm - x

H₂(g): x

S(g): x

Replacing in Kp:

$\frac{X*X}{0.150atm-X} = 0.834$

X² = 0.1251 - 0.834X

X² + 0.834X - 0.1251 = 0

Solving for X:

X = -0.964 → False solution: There is no negative pressures

X = 0.1298

Thus, pressures are:

H₂S(g): 0.150atm - 0.1298atm = <em>0.0202atm</em>

H₂(g): <em>0.1298atm</em>

S(g): <em>0.1298atm</em>

Thus, total pressure in the container at equilibrium is:

0.0202atm + 0.1298atm + 0.1298atm = <em>0.2798atm</em>

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3 years ago

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Scientists are trying to control the Maillard reaction by?​

Scientists are trying to control the Maillard reaction by?