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Vesna [10]
3 years ago
14

Scientists are trying to control the Maillard reaction by?​

Chemistry
1 answer:
dimaraw [331]3 years ago
5 0

Answer:

Intervention of Maillard reactions by the addition of natural and synthetic chemical compounds has previously been directed toward removing one of the reactants (the amino groups or the reducing sugars) or adding sulfur-containing compounds, such as sulfur dioxide or N-acetyl cysteine, which inhibit the reactions

Explanation:

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How does the energy from the sun help the tree in the process of photosynthesis?
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Using the balanced chemical reaction below, how many grams of copper (cu) metal can be obtained from 1.00 kg of copper ore (cu3f
aleksklad [387]

Answer : Mass of copper (Cu) metal obtained = 556.281 g

Solution : Given,

Mass of copper ore = 1 Kg = 1000 g

From the periodic table, the molar mass of copper and copper ore are

Molar mass of copper = 63.546 g/mole

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First we have to calculate the number of moles of copper ore, Cu_{3}FeS_{3}

Moles of  Cu_{3}FeS_{3} = \frac{\text{ Mass of copper ore}}{\text{ Molar mass of copper ore}} = \frac{1000g}{342.678g/mole} = 2.918 moles

The balanced chemical reaction is :

2Cu_{3} FeS_{3}(s)+7O_{2}(g)\rightarrow 6Cu(s)+2FeO(s)+6SO_{2}(g)

From this chemical reaction, we conclude that

2 moles of Cu_{3}FeS_{3} gives          →     6 moles of Cu

2.918 moles of Cu_{3}FeS_{3} gives   →      \frac{6moles}{2moles}\times 2.918moles

                                                           = 8.754 moles

Thus, the Moles of copper (Cu) = 8.754 moles

Now, calculate the Mass of copper (Cu).

Mass of copper (Cu) = Moles of copper (Cu) × Molar mass of copper (Cu)

                                  = 8.757 moles × 63.546 g/moles

                                  = 556.281 g                                

4 0
3 years ago
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