All categories

4 years ago

The energy of motion is called

Physics

2 answers:

Scilla [17]4 years ago

8 0

Its kinetic energy!

good day

liubo4ka [24]4 years ago

5 0

<span>A. kinetic energy. </span>

Friction converts kinetic energy into heat, and so it represents a net loss of mechanical energy. When surfaces in contact move relative to each other, the friction between the two surfaces converts kinetic energy into heat. As demonstrated by the use of friction created by rubbing pieces of wood together to start a fire, kinetic energy is converted to heat whenever motion with friction occurs. The friction produced by brake pads in a car must generate a quantity of heat equal to the kinetic energy of the car and as a result, the brakes get quite hot.

You might be interested in

Question 8 of 10

ad-work [718]

Answer:

B. Manipulated Variable

3 0

3 years ago

Read 2 more answers

Now that I know we can take pics, can someone help me?

denis23 [38]

10.D Lens 11.E Translucent 12.A Absorbtion

6 0

3 years ago

Using the formula d = rt, calculate the distance a car would travel at 80 mph for 2.5 hours.

hoa [83]

Using the formula,

$d= v \times t$

Here, d is distance, v is the velocity and t is time.

Given, $v = 80 \ mile /hour$ and $t = 2.5 \ hour$ .

Substituting these values in above formula, we get

$d = 80 \ mile /hour \times 2.5 \ hour = 200 \ miles$

Thus, the distance traveled by the car is 200 miles

8 0

3 years ago

A 1500 kg car travels 50 m north in 20 seconds. What is the magnitude of the average velocity of the car during the 20 second in

aliina [53]

Answer:

a. 2.5 m/s

Explanation:

50 / 20 = 2.5 m/s

7 0

3 years ago

You’re driving your car towards an intersection. A Porsche is stopped at the red light. You’re traveling at 36 km/h (10 m/s). As

34kurt

Your position at time $t$ , relative to the stop line:

$x_1=-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t$

The Porsche's position:

$x_2=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2$

a. You pass the Porsche immediately after the time it takes for $x_1=x_2$ :

$-15\,\mathrm m+\left(10\dfrac{\rm m}{\rm s}\right)t=\dfrac12\left(3\dfrac{\rm m}{\mathrm s^2}\right)t^2\implies t=2.3\,\rm s$

at which point you both will have traveled 7.8 m from the stop line.

b. The equation in part (a) has two solutions. The Porsche passes you at the second solution of about $t=4.4\,\rm s$ , at which point you both will have traveled 29 m.

c. At time $t$ , the Porsche is moving at velocity

$v=\left(3\dfrac{\rm m}{\mathrm s^2}\right)t$

so that at the moment it passes you, its speed is 13 m/s, which is about 46.8 km/h and below the speed limit, so neither of you will be pulled over.

6 0

4 years ago