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Anna35 [415]
3 years ago
5

Kamir and Alexis are studying the properties of water. They conducted a variety of experiments to determine its physical and che

mical properties. Of the tests the students conducted, which one illustrates a chemical property of water?
A) Salt dissolves in water.
B) Oil and water do not mix.
C) Pencil shavings float on water and do not dissolve.
D) Neutral water react s with carbon dioxide to form an acid solution.
Physics
2 answers:
Mice21 [21]3 years ago
5 0

Answer: D) Neutral water react s with carbon dioxide to form an acid solution.

Explanation: A physical property is defined as the property in which a change in shape, size takes place. No new substance gets formed while measuring physical properties.

Example: A) Salt dissolves in water.  

B) Oil and water do not mix.  

C) Pencil shavings float on water and do not dissolve.

A chemical property is defined as the property in which a change in chemical composition takes place. A new substance is formed while measuring chemical properties.

Example: D) Neutral water react s with carbon dioxide to form an acid solution.

CO_2+H_2O\rightarrow H_2CO_3

solniwko [45]3 years ago
4 0

The answer is D) neutral water reacts with carbon dioxide to form an acid solution

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In an experiment refractive index of glass was observed to be 1.45,1.56,1.54,1.44,1.54and1.53. Calculate mean value of refractiv
Sever21 [200]
The mean may be calculated by summing the values of the refractive index and dividing the sum by the number of experiments. This is:
Mean = (1.45 + 1.56 + 1.54 + 1.44 + 1.54 + 1.53)/6
Mean = 1.51

The mean absolute error is the sum of the absolute values of errors divided by the number of trials:
MAE = (|1.45-1.51|+|1.56-1.51|+|1.54-1.51|+|1.44-1.51|+|1.54-1.51|+|1.53-1.51|)/6
MAE = 0.043

The fractional error is the MAE divided by the actual value:
Fractional error = 0.043 / 1.51
Fractional error = 43/1510

The percentage error is the fractional error multiplied by 100:
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7 0
3 years ago
Um objeto de 4cm de altura está a 30cm de um espelho côncavo, cujo raio de curvatura tem valor absoluto de 20cm.
Shkiper50 [21]

a) The distance of the image from the mirror is 15 cm

b) The size of the image is -2 cm (inverted)

Explanation:

a)

We can solve this first part of the problem by applying the mirror equation:

\frac{1}{f}=\frac{1}{p}+\frac{1}{q}

where

f is the focal length

p is the distance of the object from the mirror

q is the distance of the image from the mirror

For a mirror, the focal length is half the radius of curvature, R:

f=\frac{R}{2}

For this mirror, R = 20 cm, so its focal length is

f=\frac{20}{2}=+10 cm (positive for a concave mirror)

Here we also know:

p = 30 cm is the distance of the object from the mirror

So, by applying the equation, we can find q:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}=\frac{1}{10}-\frac{1}{30}=\frac{1}{15} \rightarrow q = 15 cm

b)

We can solve this part by using the magnification equation:

M=-\frac{y'}{y}=\frac{q}{p}

where

y' is the size of the image

y is the size of the object

q is the distance of the image from the mirror

p is the distance of the object from the mirror

Here we have:

q = 15 cm

p = 30 cm

y = 4 cm

Solving for y', we find the size of the image:

y'=-y\frac{q}{p}=-(4)\frac{15}{30}=-2 cm

and the negative sign means that the image is inverted.

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