Answer:
Explanation:
The magnitude of the acceleration makes an angle of 30° with the tangential velocity.
Resolving the acceleration to tangential and radial acceleration
at = aCos30 = √3a/2
ar = aSin30 = ½a
a = 2•ar
Then, the tangential acceleration is the linear acceleration, so the relationship between the tangential acceleration and angular acceleration is given as:
at = Rα
Then, α = at/R
since at = √3a/2
Then, α = √3 at/2R, equation 1
The radial acceleration is given as
ar = ω²R
Note that, at² + ar² = a²
at = √(a²-ar²)
Back to equation 1
α = √3 at/2R
α = √3√(a²-ar²)/2R
α = √3√(a²-(w²R)²)/2R
α = √3(a²-w⁴R²) / 2R
Also, a = 2•ar = 2w²R
Then,
α = √3((2w²R)²-w⁴R²) / 2R
α = √3(4w⁴R²-w⁴R²) / 2R
α = √3(3w⁴R²) / 2R
α = √9w⁴R² / 2R
α = 3w²R / 2R
α = 3w²/2
Because their is nothing at the geographical poles that attracts the magnet
You use the right hand rule. With your thumb out and the rest of your fingers curved ( like a thumbs up) curve your fingers to the direction of the torque. The direction your thumbs points at is the direction of the torque
<span>The boat applying a force on the person pushing her forward.
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Hope this helps!
Answer:
2KI + Cl₂ → 2KCl + I₂
Explanation:
The reaction equation is given as:
KI + Cl₂ → KCl + I₂
The problem at hand is to balance this chemical reaction. To solve this problem we use a mathematical approach;
aKI + bCl₂ → cKCl + dI₂
Conserving K : a = c
I : a = 2d
Cl : 2b = c
Now let a = 1, c = 1 , d =
, b =
, ;
Multiply through by 2;
a = 2, b = 1 , c = 2, d = 1
2KI + Cl₂ → 2KCl + I₂