Two basic properties of the gas phase are

2 answers:

6 0

The choices can be found elsewhere and as follows:

A.) a definite shape and a definite volume
B.) a definite shape but no definite volume
C.) no definite shape and no definite volume

I believe the correct answer is option C. Two basic properties of the gas phase would be it has no definite shape and no definite volume. It takes the shape and volume of its container. Hope this answers the question.

qaws [65]3 years ago

4 0

Answer:

They have a very low density

They fill the container they are in

Explanation:

The first main characteristic is that they have a very low density, which is logical considering that gasses are lighter than the other states of matter (solid and liquid), however some gasses are extremely light, and some very heavy (by the relative measurement of other gasses). For example Helium is lighter than Nitrogen, so therefore we will breathe in more nitrogen than helium.

The majority of gasses are restricted to the "container" of our atmosphere, which explains why gasses never stay still, they are all trying to spread out evenly around the planet.

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A moist red litmus paper is used for testing ammonia gas ,why

yawa3891 [41]

Answer:

when the red litmus paper is placed in a jar of ammonia, the red litmus paper turns into blue as ammonia gas is basic in nature. It confirms the alkalinity of the ammonia gas.

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2 years ago

4. The reaction of silver nitrate and potassium bromide yields silver bromide and potassium nitrate. If

Hatshy [7]

Answer:

1.) AgNO₃

2.) 0.563 moles AgBr

Explanation:

The limiting reagent is the reagent that is used up completely during a reaction. It can be identified by calculating which reactant produces the smallest amount of product. This can be done by determining the number of moles of each reagent (via molarity conversion). and then converting it to moles of the product (via mole-to-mole ratio).

AgNO₃ (aq) + KBr (aq) ---> AgBr (s) + KNO₃ (aq)

Molarity (M) = moles / liters

100 mL = 1 L

AgNO₃

45.0 mL / 100 = 45.0 L

1.25 M = ? moles / 0.450 L

? moles = 0.563 moles

KBr

75.0 mL / 100 = 0.750 L

0.800 M = ? moles / 0.750 L

? moles = 0.600 moles

In this case, there is no need to use the mole-to-mole ratio because all of the coefficients are one in the reaction (the amount of the limiting reagent used is the same amount of product produced). Since AgNO₃ produces the smaller amount of product, it is the limiting reagent.

4 0

1 year ago

Consider a pot of water at 100 C. If it took 1,048,815 J of energy to vaporize the water and heat it to 135 C, how many grams of

jeka57 [31]

Answer:

There was 450.068g of water in the pot.

Explanation:

Latent heat of vaporisation = 2260 kJ/kg = 2260 J/g = L

Specific Heat of Steam = 2.010 kJ/kg C = 2.010 J/g = s

Let m = x g be the weight of water in the pot.

Energy required to vaporise water = mL = 2260x

Energy required to raise the temperature of water from 100 C to 135 C = msΔT = 70.35x