Answer:
Ionic bond
Explanation:
When the electronegativity between the two atoms is very large (usually greater than 2.1), this can lead to total transfer of electron from the higher electronegative atom to the lower one.
The total transfer of electrons leads to the formation of ionic bond.
Answer:
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Explanation:
A chemical compound has the following characteristics: (i) A chemical compound is obtained by the chemical combination of two or more elements in a definite proportion by mass. (ii) Compounds are homogeneous, i.e. their properties are the same throughout.
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The reaction between HCl and NaHCO3 will be;
HCl + NaHCO3 = NaCl + CO2 + H2O
The relative formula mass of NaHCO3 is 84 g/mol
Moles of NaHCO3 in 2 g will be; 2/84 =0.0238 moles
The mole ratio of HCl and NaHCO3 is 1;1
Thus, the number of moles of HCl is 0.0238 moles
The volume of HCl will be;
= 0.0238 moles/0.2
= 0.119 liters or 119 cm³
To determine the mass of CO₂, the following must be known :
- the molar mass of CaCO₃
- the mole ratio of CaCO₃ to CO₂
- the molar mass of CO₂
<h3>Further explanation</h3>
Reaction
Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
Given the mass of CaCO₃, so to determine the mass of CO₂ :
1. Find the mol of CaCO₃ from the molar mass of CaCO₃
2. Find the mole ratio of CaCO₃ : CO₂(from equation = 1 : 1)
3. Find the mass of CO₂ from the molar mass of CO₂
When aluminum metal is made to contact with chlorine gas (Cl₂), a highly exothermic reaction proceeds. This produces aluminum chloride (AlCl₃) powder. The balanced chemical equation for this reaction is shown below:
2Al(s) + 3Cl₂(g) → 2AlCl₃(s)
Since it was stated that aluminum is in excess, this means that the amount of AlCl₃ produced will only depend on the amount of Cl₂ gas available. The molar mass of Cl₂ is 70.906 g/mol. Using stoichiometry, we have the following equation:
(21.0 g Cl₂/ 70.906 g/mol Cl₂) x 2 mol AlCl₃/ 2 mol Cl₂ = 0.1974 mol AlCl₃
Thus, we have determined that 0.1974 <span>moles of aluminum chloride can be produced from 21.0 g of chlorine gas. </span>
