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Likurg_2 [28]
3 years ago
12

What molecule is needed to digest milk?

Chemistry
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

For example, the sugar found in milk is called lactose. With the aid of the enzyme, lactase, the substrate, lactose, is broken down into two products, glucose and galactose. People who don't make enough lactase have trouble digesting milk products and are lactose intolerant.

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For the unbalanced equation, what is the coefficient for c5h10 ?
marshall27 [118]
The answer is the coefficient is "1".
C₅H₁₀, now you see that there is no number with this and when there is no number or digit, it means the coefficient is one.
we use the coefficients to balance the equation of the reaction in such a way that number of the atoms of the elements in the reactants are equal to the number of atoms of different elements in the product, so that both sides are equal and balanced.
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4 years ago
A child sits on a partially filled balloon and decreases the volume by half. What happens to the pressure inside of the balloon?
nordsb [41]
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HELP PLZZ
Greeley [361]

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5 0
3 years ago
What is gadolinium<br><br> And what would be a superpower that relates to it
hjlf

Answer:

Chemical with symbol Gd on periodic table of elements. It reacts with oxygen.

Fire superpower i guess

Explanation:

6 0
2 years ago
Aconitase catalyzes the citric acid cycle reaction: citrate &lt;==&gt; isocitrate. The standard free energy change, ΔGo ’, for t
rjkz [21]

Answer:

A. [isocitrate]/[citrate] = 0.724

B. [citrate] = 24.1 mM

Explanation:

Using the equation, ∆G'° = -RTlnK'eq

Where, ∆G'° = 0.8 KJ/mol = 800 J/mol; R is molar gas constant = 8.315 J/mol; T is standard temperature = 298 K; Keq is equilibrium constant = [isocitrate]/[citrate]

Making Keq subject of formula in the above equation;

Keq = e^(-∆G'°/RT)

= e^ {-800/(8.315*298)}

= e^(-0.323)

Keq = 0.724

Therefore, [isocitrate]/[citrate] = 0.

724

B. Keq = [isocitrate]/[citrate]

Where Keq = 0.724, [isocitrate] = 0.03mM.

[citrate] = Keq/[isocitrate]

= 0.724/0.03

[citrate] = 24.1 mM

5 0
3 years ago
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