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Answer:
Please find the ten balanced equations below
Explanation:
According to the question, a balanced equation must contain equal number of atoms on both sides of the equation. To balance an equation, coefficients are used. The following are the balanced equation:
1. C + O2 → CO2 (balanced)
2. 2H2 + O2 → 2H2O (balanced)
3. 2Na + 2H2O → 2NaOH + H2 (balanced)
4. 4Na + O2 → 2Na2O (balanced)
5. 2Na + Cl2 → 2NaCl (balanced)
6. NaOH + HCl → NaCl + H2O (balanced)
7. NaOH + HNO3 → NaNO3 + H2O (balanced)
8. 2NaOH + H2SO4 → Na2SO4 + 2H2O (balanced)
9. Na2CO3 + 2HCl → 2NaCl + H2O + CO2 (balanced)
10. 2NaOH + CO2 → Na2CO3 + H2O (balanced)
The equation is as below,
<span>5 Ag</span>⁺ (aq) + Mn²⁺ <span>(aq) + 4H</span>₂<span>O (l) → 5Ag (s) + MnO4</span>⁻<span>(aq) + 8H</span>⁺ <span>(aq)
Reduction:
According to eq. Silver is reduced as,
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5 Ag⁺ + 5 e⁻ → 5 Ag
One electron is gained per Ag ion, so 5 Ag ions will gain 5 electrons.
Oxidation:
According to eq. Manganese is Oxidized as,
Mn²⁺ → MnO4⁻
Oxidation number of Mn in MnO₄⁻ is +7, so Mn²⁺ is loosing 5 electrons, Hence,
Mn²⁺ → MnO4⁻ + 5 e⁻
Results:
Hence, 5 moles of electrons are exchanged between oxidizing and reducing agents.