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xeze [42]
3 years ago
11

4(y+6)+5y this irritating

Mathematics
1 answer:
Alla [95]3 years ago
4 0
I'm guessing you have to simplify this?
You distribute 4 to whatever is in the parenthesis.

So
4•y=4y
4•6=24
And of course there's the 5y that stays the same.

You get 4y+24+5y
Which simplifies to 9y+24 because you can group the 4y and 5y together.

In the end, you get 9y+24.
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How many toys were stuffed animals
Umnica [9.8K]

Answer:

It would be the first one.

Step-by-step explanation:

The way you figure it out is that it said that there was a total of 80 stuffed animals, so model B is out. Then, you change the percent into a decimal by moving the decimal point over to the right 2 times and you get 0.30. Finally, you multiply 80 by 0.30 and you get 24 stuffed animals.

4 0
3 years ago
Read 2 more answers
| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
Westkost [7]

Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

3 0
2 years ago
A scientist
Nady [450]
It’s 5,905 bc you need to add all of you distilled water to know if you have enough
7 0
3 years ago
Factor 5a^2-30a+45, and 2x^5+x^4-2x-1.
Mrrafil [7]

Step-by-step explanation:

{5a}^{2}  - 30a + 45

5( {a}^{2}  - 6a + 9)

5(a-3)(a-3)

5(a-3)^2

{2x}^{5}  +  {x}^{4}  - 2x - 1

X^4(2x+1) - (2x+1)

(x^4-1)(2x+1)

(x^2-1)(x^2+1)(2x+1)

(x-1)(x-1)(x^2+1)(2x+1)

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Please mark Brainliest
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