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umka2103 [35]
3 years ago
7

Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba

ll’s journey will gravity be the greatest force acting on the ball?
Physics
1 answer:
PolarNik [594]3 years ago
3 0

Answer:

If air resistance is taken as negligible, then the ball is in freefall the moment it is thrown so gravity is the only force acting on the object. If air resistance is not negligible then gravity will be the greatest force acting on the ball while it is going up and coming down, because Fair has to be less than gravity at all times otherwise the atmosphere would wither away.

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Production of electricity from nuclear energy is a lot more expensive than production of energy from fossil fuels

Explanation:

uranium is one of the rarest elements on earth, its more expensive than gas and oil, and it makes the same if not more pollution.

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Find the odd one out radish,potato, beet,carrot.​
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4 years ago
Read 2 more answers
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 13.0 m/s when the
My name is Ann [436]

Answer:

2.82 s

Explanation:

The ball will be subject to the acceleration of gravity which can be considered constant. Therefore we can use the equation for uniformly accelerated movement:

Y(t) = Y0 + Vy0 * t + 1/2 * a * t^2

Y0 is the starting position, 2.3 m in this case.

Vy0 is the starting speed, 13 m/s.

a will be the acceleration of gravity, -9.81 m/s^2, negative because it points down.

Y(t) = 2.3 + 13 * t - 1/2 * 9.81 * t^2

It will reach the ground when Y(t) = 0

0 = 2.3 + 13 * t - 1/2 * 9.81 * t^2

-4.9 * t^2 + 13 * t + 2.3 = 0

Solving this equation electronically gives two results:

t1 = 2.82 s

t2 = -0.17 s

We disregard the negative solution. The ball spends 2.82 seconds in the air.

7 0
3 years ago
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