Matthew throws a ball straight up into the air. It rises for a period of time and then begins to drop. At which points in the ba
1 answer:
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Since rope is parallel to the inclined plane so here we can say that net force parallel to the person which is pulling upwards must counterbalance the component of weight of the person.
Now here we will do the components of the weight of the person
given that weight of the person = 500 N
now its components are
now here as we can say that one of the component is balanced here by the normal force perpendicular to plane
while the other component of the weight is balanced by the force applied on the rope
So here the force applied on the rope will be given as
so it apply 300 N force along the inclined plane
Answer:
magnitude: 21.6; direction: 33.7 degrees
Explanation:
When we multiply a vector by a scalar, we have to multiply each component of the vector by the scalar number. In this case, we have
vector: (-3,-2)
Scalar: -6
so the vector multiplied by the scalar will have components
The magnitude is given by Pythagorean's theorem:
and the direction is given by the arctan of the ratio between the y-component and the x-component: