27. The traffic officer issued violation tickets to traffic
1 answer:
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Answer:
La fuerza magnética del electrón es 6.41x10⁻¹³ N.
Explanation:
Podemos encontrar la fuerza magnética (F) usando la ley de Lorentz:
En donde:
q: es la carga del electrón = 1.602x10⁻¹⁹ C
v: es la velocidad del electrón = 5x10⁶ m/s
B: es el campo magnético = 0.8 T
Por lo tanto, la fuerza magnética del electrón es 6.41x10⁻¹³ N.
Espero que te sea de utilidad!
Answer:
Magnetic field,
Explanation:
It is given that,
Number of turns, N = 320
Radius of the coil, r = 6 cm = 0.06 m
The distance from the center of one coil to the electron beam is 3 cm, x = 3 cm = 0.03 m
Current flowing through the coils, I = 0.5 A
We need to find the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils. The magnetic field midway between the coils is given by :
B = 0.00239 T
or
So, the magnitude of the magnetic field at a location on the axis of the coils, midway between the coils is . Hence, this is the required solution.