Answer:
water evaporates into the atmosphere
Answer:
-7.5 kg m/s
Explanation:
Initial momentum (p1) = 4.5 kg m/s
final momentum (p2) = -3.5 kg m/s
We have to find out the change in momentum , As linear momentum is a vector quantity. So, we have to use the vector form to solve the momentum change . Means we have to take the sign of momentum also.
Change in momentum = Final momentum - initial momentum
So,
Change in momentum = p2 - p1
Insert values from question,
Change in momentum = -3.5 kg m/s - 4 kg m/s
So, change in momentum = -7.5 kg m/s
Answer:
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Explanation:
For laminar flow between two parallel horizontal plates, the volumetric flow per metre of width is given as
q = (2h³/3μ) (ΔP/L)
h = hydraulic depth = 4mm/2 = 2mm = 0.002 m
μ = viscosity of oil (SAE 30) at 15.6°C = 0.38 Pa.s
(ΔP/L) = 26 KPa/m = 26000 Pa/m
q = (2h³/3μ) (ΔP/L)
q = (26000) × (2(0.002³)/(3×0.38))
q = 0.0003649123 m²/s = (3.65 × 10⁻⁴) m²/s
Well, the spring constant is measured using the F=k∆x, where F is the force, k is the constant, and ∆x is the change in position. So if the mass is 1.98, the force (mxg) is 19.4. Thus the spring constant is 19.4/.0478(change in position). This equals 405.86.
