Answer:
3.0 moles Al₂O₃
Explanation:
We do not know which of the reactants is the limiting reactant. Therefore, you need to convert both of the given mole values into the product. This can be done using the mole-to-mole ratio made up of the balanced equation coefficients.
4 Al + 3 O₂ -----> 2 Al₂O₃
6.0 moles Al 2 moles Al₂O₃
---------------------- x ------------------------- = 3.0 moles Al₂O₃
4 moles Al
4.0 moles O₂ 2 moles Al₂O₃
---------------------- x ------------------------- = 2.7 moles Al₂O₃
3 moles O₂
As you can see, O₂ produces the smaller amount of product. This means O₂ is the limiting reactant. Remember, the limiting reactant is the reactant which runs out before the other reactant(s) are completely reacted. As such, the actual amount of Al₂O₃ produced is 2.7 moles.
However, since this problem is directly addressing how much Al₂O₃ is produced from Al, the answer you most likely are looking for is 3.0 moles Al₂O₃.
Answer:
Explanation:
a. the salt produced would be Mg3N2(magnesium nitride)
b. magnesium loses 2 electron to form Mg2+ ion and nitrogen gains 3 electron to form n3-
when several of these ions come together 3 Mg2+ ion combine with 2 n3- ion to form Mg3N2 thus Mg getting six electron from nitrogen to form a ionic bond.
c. the reaction is not balanced Mg + N2 = Mg3n2
to make it balanced the reaction should be 3 Mg + N2 = Mg3N2.
the reaction was not balanced before because the number of Mg on both side of the reaction was not equal.
d. magnesium nitrate has formula Mg(NO3)2 is formed when Mg combines with nitrogen and oxygen Mg + N2 + o2
Answer:
melting point
Explanation:
Phase changes happen when you reach certain special points. Sometimes a liquid wants to become a solid. Scientists use something called a freezing point or melting point to measure the temperature at which a liquid turns into a solid. There are physical effects that can change the melting point.
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Answer:
2060.775 J
Explanation:
From the question given above, we obtained the following data:
Specific heat capacity (C) = 0.129 J/g°C
Mass (m) = 355 g
Initial temperature (Tᵢ) = 95 °C
Final temperature (Tբ) = 140 °C
Heat (Q) tranfered =?
We can calculate the amount of heat transferred by using the following formula:
Q = mC(Tբ – Tᵢ)
Q = 355 × 0.129 (140 – 95)
Q = 45.795 × 45
Q = 2060.775 J
Thus, 2060.775 J of energy was transferred.