A is the correct answer i really hope this helps!
The question is incomplete, here is the complete question.
A chemist prepares a solution of copper(II) fluoride by measuring out 0.0498 g of copper(II) fluoride into a 100.0mL volumetric flask and filling the flask to the mark with water.
Calculate the concentration in mol/L of the chemist's copper(II) fluoride solution. Round your answer to 3 significant digits.
<u>Answer:</u> The concentration of copper fluoride in the solution is 
<u>Explanation:</u>
To calculate the molarity of solute, we use the equation:
We are given:
Given mass of copper (II) fluoride = 0.0498 g
Molar mass of copper (II) fluoride = 101.54 g/mol
Volume of solution = 100.0 mL
Putting values in above equation, we get:
Hence, the concentration of copper fluoride in the solution is
<span>The solubilties of most ionic solids increase as the temperature increases.
Dissolving of a solid in water is, in most cases, an endothermic
reaction. In dissolving, as in melting, a solid becomes a liquid. It
takes more energy to be a liquid than to be a solid at the same
temperature. When the solution becomes saturated at any temperature, a
dynamic equilibrium is established between the dissolved and undissolved
solid. When heat is added that results in a higher temperature, the
extra heat favors the endothermic reaction, and more solid dissolves
rather than crystallizes until new equilibrium system is established
again. Hence, at a higher temperature, more solid is dissolved in
water. This increases the solid's solubility.
Hope this helps mate =)
</span>
Answer:
Explanation:
Reducing agent
Reducing agent is an element or compound that loses or donates an electron to another chemical species in a redox chemical reaction. Since the reducing agent is losing electrons,it is said to have been oxidized.
Answer is D.
Have a nice day.
