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lukranit [14]
3 years ago
15

Angelina jumps off a stool. As she is falling, the Earth’s gravitational force on her is larger in magnitude than the gravitatio

nal force she is exerting on the earth. 1. False 2. This may happen in many cases, but not in every case. 3. True 4. None of these 5. This may happen in a few cases, but it is very rare.
Physics
2 answers:
valentinak56 [21]3 years ago
8 0
The answer is True. The amount force exerted by any object is directly proportional to its mass. This means that our planet is exerting more gravitational force to Angelina, and Angelina is also exerting a gravitational force on our planet directly proportional to her mass. Angelina is actually falling towards the center of the earth,and also our planet is also moving towards Angelina, but it seems negligible with respect to Angelina.Our Sun is so massive that it held our planet in its orbit because of its gravitational force.
STatiana [176]3 years ago
5 0

Answer:

1. False

Explanation:

As per law of gravitational attraction force we know that

F = \frac{Gm_1m_2}{r^2}

where we know that

m_1,m_2 = masses of two point mass

r = distance between two masses

so here we know that as the force does not depend on individual mass but it will depend on the product of two masses

so here the gravitational force is same in magnitude on both the bodies

so when Angelina jumps off the stool the gravitational force on Earth and on Angelina must be of same magnitude

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The world’s largest wind turbine has blades that are 80 m long and makes 1 revolution every 5.7 seconds. What is the velocity fo
klemol [59]

Answer:

The free end of the blade has a tangential velocity of about 88.19 m/s

Explanation:

The angular velocity of the blades is  2 \pi /5.7\,\,rad/sec

since the blades are 80 m long, then the tangential velocity of the free end of the blade is:

v_{tan} \approx 88.19\,\,m/s

3 0
3 years ago
The principle of work states that the ratio of work output to work input is always
snow_lady [41]

Answer:

work output is always less than work input - the ratio is less than 1.

Explanation:

This principle comes from the fact that a machine or system cannot produce more work than is supplied to it, because this would violate the energy conservation law (work is a type of mechanical energy).

In theoretical machines called "ideal machines" the input work is the same as the output work, but these machines are only theoretical because in real applications there is always some type of energy loss, either in heat produced by a machine or processes for its operation, for this reason the output work is always less than the input work.

Regarding the ratio work output to work input:

\frac{WO}{WI} < 1

because work input WI is always greater than work output WO.

7 0
3 years ago
PLEASEEE HELPPPP
solniwko [45]

Answer:

Explanation:

average speed more than 25.0m/s.

5 0
3 years ago
Read 2 more answers
The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static fricti
Colt1911 [192]

This question is incomplete, the complete question;

The L-ft ladder has a uniform weight of W lb and rests against the smooth wall at B. θ = 60. If the coefficient of static friction at A is μ = 0.4.

Determine the magnitude of force at point A and determine if the ladder will slip. given the following; L = 10 FT, W = 76 lb

Answer:

- the magnitude of force at point A is 79.1033 lb

- since FA < FA_max; Ladder WILL NOT slip

Explanation:

Given that;

∑'MA = 0

⇒ NB [Lsin∅] - W[L/2.cos∅] = 0

NB = W / 2tan∅ -------let this be equation 1

∑Fx = 0

⇒ FA - NB = 0

FA = NB

therefore from equation 1

FA = NB = W / 2tan∅

we substitute in our values

FA = NB = 76 / 2tan(60°) = 21.9393 lb

Now ∑Fy = 0

NA - W = 0

NA = W = 76 lb

Net force at A will be

FA' = √( NA² + FA²)

= √( (W)² + (W / 2tan∅)²)

we substitute in our values

FA' = √( (76)² + (21.9393)²)

= √( 5776 + 481.3328)

= √ 6257.3328

FA' = 79.1033 lb

Therefore the magnitude of force at point A is 79.1033 lb

Now maximum possible frictional force at A

FA_max = μ × NA

so, FA_max = 0.4 × 76

FA_max = 30.4 lb

So by comparing, we can easily see that the actual friction force required for keeping the the ladder stationary i.e (FA) is less than the maximum possible friction available at point A.

Therefore since FA < FA_max; Ladder WILL NOT slip

5 0
2 years ago
Compare and contrast sound waves and electromagnetic waves. Any bs answers will be reported. Please hurry!!!
Trava [24]

Answer:

They are both forms of energy.  One has to do with hearing and the other a little bit of light.

Explanation:

3 0
2 years ago
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