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3 years ago

NEED HELP ASAP!!!!!!!!!!!!!!

Mathematics

2 answers:

Ainat [17]3 years ago

6 0

Simplifying both sides of the equation then isolating the variable.

so the answer is... w=48

FrozenT [24]3 years ago

3 0

28 = w/4 + 16....subtract 16 from both sides
28 - 16 = w/4
12 = w/4....multiply both sides by 4
12 * 4 = w
48 = w <===

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3 years ago

Given \qquad m \angle LONm∠LONm, angle, L, O, N is a straight angle. \qquad m \angle MON = 8x - 13^\circm∠MON=8x−13 ∘ m, angle,

Tamiku [17]

Answer:

<h3> $\boxed{99°}$ </h3><h3 />

Step-by-step explanation:

m<MON = 8x - 13°

m<LOM = 7x - 17°

To find : m <MON

First, we have to find the value of x :

Create an equation

$\mathrm{8x - 13 + 7x - 17 = 180}$ ( sum of angle in straight line )

Collect like terms

$\mathrm{15x - 13 - 17 = 180}$

Calculate

$\mathrm{15x - 30 = 180}$

Move constant to R.H.S and change its sign

$\mathrm{15x = 180 + 30}$

Calculate the sum

$\mathrm{15x = 210}$

Divide both sides of the equation by 15

$\mathrm{ \frac{15x}{15} = \frac{210}{15} }$

Calculate

$\mathrm{x = 14}$

Now, let's find the value of m<MON

$\mathrm{8x - 13}$

Plug the value of x

$\mathrm{ = 8 \times 14 - 13}$

Calculate the product

$\mathrm{ = 112 - 13}$

Calculate the difference

$\mathrm{ = 99}$ °

Hope I helped!

Best regards!

6 0

2 years ago

Which of these values for p and a will cause the function f(x)=Pax to be an exponential growth function

vovikov84 [41]

The option are missing in the question. The options are :

A. P = 2, a = 1

B. $P=\frac{1}{2} ; a =\frac{1}{3}$

C. $P=\frac{1}{2} ; a =1$

D. P = 2, a = 3

Solution :

The given function is $f(x)= Pa^x$

So for the function to be an exponential growth, a should be a positive number and should be larger than 1. If it less than 1 or a fraction, then it is a decay. If the value of a is negative, then it would be between positive and negative alternately.

When the four option being substituted in the function, we get

A). It is a constant function since $2(1^x)=2$

B). Here, the value of a is a fraction which is less than 1, so it is a decay function. $f(x)=\frac{1}{2}\left(\frac{1}{3}\right)^x$

C). It is a constant function since the value of a is 1.

D). Here a = 3. So substituting, as the value of x increases by 1, the value of the function, f(x) increases by 3 times.

$f(x)=2(3)^x$

Therefore, option (D). represents an exponential function.

4 0

2 years ago