Answer:
The percentage yield of O2 is 66.7%
Explanation:
Reaction for decomposition of potassium chlorate is:
2KClO₃ → 2KCl + 3O₂
The products are potassium chloride and oxygen.
Let's find out the moles of chlorate.
Mass / Molar mass = Moles
12.3 g / 123 g/mol = 0.1 mol
So ratio is 2:3, 2 moles of chlorate produce 3 mol of oxygen.
Then, 0.1 mol of chlorate may produce (0.1 .3)/ 2 = 0.15 moles
Let's convert the moles of produced oxygen, as to find out the theoretical yield.
0.15 mol . 32 g/ 1mol = 4.8 g
To calculate the percentage yield, the formula is
(Produced Yield / Theoretical yield) . 100 =
(3.2g / 4.8g) . 100 = 66.7 %
The statements that describe a nuclear reaction are may involve a change in total mass, involve very high-energy changes, and involve changes in nuclides when decay takes place.
There are two kinds of nuclear reactions, that is, fission and fusion. Fusion involves the fusion of two light atoms into a heavier atom, while fission involves the splitting of an unstable isotope (with a high mass number) into stable elements of lower mass number, which vary in features from the parent atoms. Both the reactions discharge huge concentration of energies in the process.
<u>Answer:</u> The balanced chemical equation is 
<u>Explanation:</u>
A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.
For the given unbalanced chemical equation:

<u>On the reactant side:</u>
Atoms of K = 1
Atoms of Cl = 1
Atoms of O = 3
<u>On the product side:</u>
Atoms of K = 1
Atoms of Cl = 1
Atoms of O = 2
To balance the equation, we must balance the atoms by adding 2 infront of both
and
. Also, a coefficient of 3 must be written infront of 
For the balanced chemical equation:

Answer:
The alkyl halide is secondary
The nucleophile is a poor nucleophile
The solvent is a protic solvent
The product is racemic
Explanation:
The reaction is shown in the image attached.
Alkyl halides undergo nucleophilic substitution by two mechanisms; SN1 and SN2. The particular mechanism that applies depends on;
I) structure of the alkyl halide
ii) nature of the nucleophile
iii) nature of the solvent
Looking at the reaction under review, we can see from the structure that the alkyl halide is a secondary alkyl halide. A secondary alkyl halide may undergo substitution via SN1 or SN2 mechanism depending on the conditions of the reaction.
If the nucleophile is poor, and the solvent is protic, SN1 mechanism is favoured over SN2 mechanism. Since CH3CH2OH is a poor nucleophile and ethanol is a protic solvent, we expect the reaction to proceed via SN1 mechanism leading to the formation of a racemic product.
The organic product is also shown in the second image attached.