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schepotkina [342]
3 years ago
15

What is the normality of a solution containing 14.8 g of Ca(OH)₂ in 250.0 mL?

Chemistry
1 answer:
aliina [53]3 years ago
6 0

Answer:

Explanation:Are You From Milo?

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gulaghasi [49]

Answer:

A directory of relatives' phone numbers

Hope this helps

Explanation:

5 0
3 years ago
Lab 27. stoichiometry and chemical reactions: which balanced chemical equation best represents the thermal decomposition of sodi
Cloud [144]
Answer:
             Sodium Bicarbonate on decomposition produces Carbon dioxide gas and Water vapors.

<span>                       2 NaHCO</span>₂<span> </span> →<span>  Na</span>₂<span>CO</span>₃<span> (s)  </span>+ <span> CO</span>₂<span> (g)  +  H</span>₂<span>O (g)
</span>
Explanation:
                   Let suppose you burn 168 g ( 2 moles ) of NaHCO₃, a gas will produced and product is left behind. On measuring the product formed it will be almost equal to 105 g. This shows that the product is Na₂CO₃ and 1 mole of it is being produced after decomposition of sodium bicarbonate.
5 0
3 years ago
If you start with 0.30 m mn2 , at what ph will the free mn2 concentration be equal to 4.6 x 10-11 m?
aksik [14]

If you start with 0.30 m Mn₂ , at 12.5 pH, free Mn₂ concentration be equal to 4.6 x 10⁻¹¹ m

Initial molarity of Mn₂ = 0.30 M

Final molarity of Mn₂ = 4.6 x 10⁻¹¹

pH = ?

Ksp [Mn(OH)₂] = 4.6 x 10⁻¹⁴ (standard value)

Write the ionic equation

    Mn(OH)₂   →    Mn⁺² + 2OH⁻

    [Mn⁺²] = 4.6 x 10⁻¹¹

We will calculate the concentration of OH⁻ by using Ksp expression

    Ksp = [Mn⁺²][OH-]²

    [Mn⁺²][OH⁻]² = 4.6 x 10⁻¹⁴

    [OH⁻]² = 4.6 x 10⁻¹⁴ / 4.6 x 10⁻¹¹

    [OH⁻]² = 10⁻³

    [OH⁻] = (10⁻³)¹⁽²

    [OH⁻] = 0.0316 M

Calculate the pOH

    pOH = -log [OH⁻]

    pOH =  -log [0.0316]

    pOH = 1.5

Now calculate pH

   pH = 14 - pOH

   pH = 14 - 1.5

   pH = 12.5

You can also learn about molarity from the following question:

brainly.com/question/14782315

#SPJ4

7 0
1 year ago
PLEASE HELP! DUE IN 5 MINUTES! ( 10 points )
max2010maxim [7]

Answer:

C

Explanation:

3 0
3 years ago
Read 2 more answers
The p subshell can hold up to eight electrons in an atom (2 points)<br> True or false?
hoa [83]

Answer: The statement is false

Explanation:

Electrons occupy a region in atoms known as orbitals or subs hell.  These orbitals include

I) S-orbital: it can occupy a maximum of two electrons

II) P-orbital: It occupies a maximum of six electrons

III) D-orbital: it occupies a maximum of ten electrons

F and G-orbitals as examples of other orbitals present.

A good illustration of the 6 electrons occupied by the P-subshell is seen in Sodium (Na) with atomic number of 11

Na = 1s2, 2S2 2p6, 3s1

Note: extra electrons are transferred to the next orbital

8 0
3 years ago
Read 2 more answers
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