PLEASE HELP I AM FAILING

Is a dibasic acid the same as a strong acid

Kisachek [45]

Answer:

Since all the acid molecules have split into ions, there will be more H+ ions in a strong acid than a weak acid, hence it's pH is lower! E.g. Hydrochloric acid HCl, nitric acid HNO3. If one mole of an acid is neutralised by 2 moles of NaOH, then the acid is dibasic!

Explanation:

hope it helps

good day

thank u ✌️

7 0

3 years ago

Read 2 more answers

This is the word geologists use for loose pieces of minerals and rock. The particles are transported by wind, water, or ice, and

qaws [65]

<span>Sediments
Sediments are solid materials that were broken down by the process of erosion, weather and transported by the water, wind or glaciers and then deposited in a new location. Sediment can consist of minerals and rocks and can be as small as a grain of sand or as large as a boulder.</span>

7 0

3 years ago

Read 2 more answers

Why do cells divide?

Zielflug [23.3K]

Cells divide for so living things can grow

5 0

3 years ago

A mixture of nitrogen and xenon gases contains nitrogen at a partial pressure of 251 mm Hg and xenon at a partial pressure of 47

klio [65]

I uploaded the answer to a file hosting. Here's link:

tinyurl.com/wpazsebu

3 0

3 years ago

How would you make a 2.00L of 0. 500M sodium chloride solution. (assume you have a fully equipped lab with water); sketch, calc

Gwar [14]

Answer:

Sodium chloride solution:

First you need to calculate the mass of salt needed (done in the explanation), which is 58.44g. Then it have to be weighted in an analytical balance in a weighting boat and then transferred into a 2L volumetric flask that is going to be filled until the mark with distilled water.

Sulfuric acid dilution:

First you need to calculate the volume needed (done in the explanation), it is 16.6 mL. Using a graduated pipette one measures this volume and transfer it into a 2L volumetric flask that is already half filled with distilled water, and then one fills it until its mark.

Explanation:

Sodium chloride solution:

Each liter of a 0.500M solution has half mol, so 2L of said solution has 1 mol of salt. Sodium chloride molar mass is 58.44g/mol, so in 2L of solution there is 58.44g of salt. That`s the mass that`s going to be weighted and transferred to a 2L volumetric flask.

Sulfuric acid dilution:

This is the equation for dilution of solutions:

$c_{1} v_{1} =c_{2} v_{2}$

Where "c1" stands for the initial concentration (stock solution concentration), "v1" for the initial volume (volume of stock solution used), "c2" for the desired concentration and "v2" for the desired volume.

When we are diluting from a stock solution we want to know how much do we have to pipette from the stock solution into our volumetric flask. We do so by isolating the "v1" term from the dilution equation:

$v_{1} =\frac{c_{2} v_{2} }{c_{1} }$

in this case that would be:

$v_{1} =\frac{0.100 x2.0 }{12.0 }=0.0166L=16.6mL$

5 0

3 years ago