1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
777dan777 [17]
3 years ago
7

A 4.40-kilogram hoop starts from rest at a height 1.70 m above the base of an inclined plane and rolls down under the influence

of gravity. What is the linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface
Physics
2 answers:
Anestetic [448]3 years ago
4 0

Answer:

The linear velocity is  v=4.08m/s

Explanation:

According to the law of conservation of energy

   The potential energy possessed by the  hoop at the top of the inclined plane is converted to the kinetic energy at the foot of the inclined plane

        The kinetic energy can be mathematically represented as

                    KE = \frac{mv^2}{2} + \frac{Iw}{2}

Where I is the moment of inertia possessed by the hoop  which is mathematically represented as

                 I = mr^2

Here R is the radius of the hoop

         w is the angular velocity which the hoop has at the bottom of the lower part of the inclined plane which is mathematically represented as

                          w = \frac{v}{r}

Where v linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface

      Now expressing the above statement mathematically

            potential \ energy = \frac{mv^2}{y} + \frac{Iw^2}{2}

               mgh = \frac{mv^2}{y} + \frac{Iw^2}{2}

=>            mgh =\frac{mv^2}{2} + \frac{(mr^2)(\frac{v}{r})^2 }{2}  

=>          mgh = \frac{mv^2}{2} + \frac{mv^2}{2}

=>           mgh = mv^2

=>              v = \sqrt{gh}

Substituting values

                v = \sqrt{9.81 * 1.7}

                  v=4.08m/s

Alexandra [31]3 years ago
3 0

Answer:

vcm = 4.08 m/s

Explanation:

  • Assuming the inclined plane is frictionless, and that the hoop is rolling without slippling, the total mechanical energy of the hoop must be conserved:

        \Delta K + \Delta U = 0     (1)

  • As the hoop starts from rest, the change in kinetic energy will be equal to the final kinetic energy of the hoop.
  • This kinetic energy will have a part of rotational kinetic energy (due to the rotation around an axis passing through the center of the hoop), and a translational part, due to the translation of the center of mass.
  • This kinetic energy can be written as follows:

        K_{tot} = \frac{1}{2} * I_{hoop} *\omega^{2} +  \frac{1}{2} * m *v_{cm}^{2}  (2)

  • where Ihoop, is the moment of inertia of the hoop = m*r².
  • If the hoop rolls without slipping, there exists a fixed relationship between the angular velocity ω and the velocitity of the center of mass vcm, as follows:

        \omega = \frac{v_{cm} }{r}

  • Replacing the values of  I and ω in (2), we have:

       K_{tot} = \frac{1}{2} * m*r^{2} * (\frac{v_{cm} }{r} )^{2}  +  \frac{1}{2} * m *v_{cm}^{2} = \\ \\ K_{tot} = m*v_{cm} ^{2}

  • This change in kinetic energy must be equal to the change in gravitational potential energy.
  • If we choose as our zero reference level the bottom of the incline, the change in gravitational potential energy is as follows:

       \Delta U = U_{f} - U_{o} = 0 - m*g*h = - m*g*h

  • From (0), simplifying common terms and rearranging, we can solve for vcm, as follows:
  • v_{cm} =\sqrt{g*h} =\sqrt{1.70 m* 9.8 m/s2  } = 4.08 m/s
You might be interested in
1. The diagram shows a satellite traveling in uniform circular motion around the Earth.
FromTheMoon [43]

Answer:

M V R = constant      angular momentum is constant because  no forces act in the direction of V

Since M (mass) = constant

V R = constant

The force is directed along the gravitational force vector (towards the center of rotation)

6 0
2 years ago
Material that slows down or resists the flow of current. these are used in electric circuits to help control the flow of current
Nataly_w [17]
It's called an insulator

3 0
3 years ago
A particle initially located at the origin has an acceleration of vector a = 2.00ĵ m/s2 and an initial velocity of vector v i =
natali 33 [55]

With acceleration

\mathbf a=\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)\,\mathbf j

and initial velocity

\mathbf v(0)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i

the velocity at time <em>t</em> (b) is given by

\mathbf v(t)=\mathbf v(0)+\displaystyle\int_0^t\mathbf a\,\mathrm du

\mathbf v(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\displaystyle\int_0^t\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)\,\mathbf j\,\mathrm du

\mathbf v(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf j\bigg|_{u=0}^{u=t}

\mathbf v(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)t\,\mathbf j

We can get the position at time <em>t</em> (a) by integrating the velocity:

\mathbf x(t)=\mathbf x(0)+\displaystyle\int_0^t\mathbf v(u)\,\mathrm du

The particle starts at the origin, so \mathbf x(0)=\mathbf0.

\mathbf x(t)=\displaystyle\int_0^t\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)u\,\mathbf j\,\mathrm du

\mathbf x(t)=\left(\left(8.00\dfrac{\rm m}{\rm s}\right)u\,\mathbf i+\dfrac12\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)u^2\,\mathbf j\right)\bigg|_{u=0}^{u=t}

\mathbf x(t)=\left(8.00\dfrac{\rm m}{\rm s}\right)t\,\mathbf i+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)t^2\,\mathbf j

Get the coordinates at <em>t</em> = 8.00 s by evaluating \mathbf x(t) at this time:

\mathbf x(8.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)(8.00\,\mathrm s)\,\mathbf i+\left(1.00\dfrac{\rm m}{\mathrm s^2}\right)(8.00\,\mathrm s)^2\,\mathbf j

\mathbf x(8.00\,\mathrm s)=(64.0\,\mathrm m)\,\mathbf i+(64.0\,\mathrm m)\,\mathbf j

so the particle is located at (<em>x</em>, <em>y</em>) = (64.0, 64.0).

Get the speed at <em>t</em> = 8.00 s by evaluating \mathbf v(t) at the same time:

\mathbf v(8.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(2.00\dfrac{\rm m}{\mathrm s^2}\right)(8.00\,\mathrm s)\,\mathbf j

\mathbf v(8.00\,\mathrm s)=\left(8.00\dfrac{\rm m}{\rm s}\right)\,\mathbf i+\left(16.0\dfrac{\rm m}{\rm s}\right)\,\mathbf j

This is the <em>velocity</em> at <em>t</em> = 8.00 s. Get the <em>speed</em> by computing the magnitude of this vector:

\|\mathbf v(8.00\,\mathrm s)\|=\sqrt{\left(8.00\dfrac{\rm m}{\rm s}\right)^2+\left(16.0\dfrac{\rm m}{\rm s}\right)^2}=8\sqrt5\dfrac{\rm m}{\rm s}\approx17.9\dfrac{\rm m}{\rm s}

5 0
3 years ago
What land form is created when magma squeezes between rock layers to form a hardened slab of rock? a. volcanic neck b. ike c. la
valentina_108 [34]
D is your answer sill glad to help!
8 0
3 years ago
Read 2 more answers
If a population is growing what can you conclude about the ammount of resources available
Elodia [21]

Answer:

Generally speaking, as the human population grows, our consumption of natural resources increases. More humans consume more freshwater, more land, more clothing, etc. ... For example, natural gas plants have become increasingly more efficient, thus humans are able to obtain more energy out of the same amount of gas.

Rapid population growth is detrimental to achieving economic and social progress and to sustainable management of the natural resource base. But there remains a sizeable gap between the private and social interest in fertility reduction, and this gap needs to be narrowed.

7 0
2 years ago
Other questions:
  • lens is to be used to allow this eye to clearly focus on objects 25 cm in front of it. What should be the focal length of this l
    9·1 answer
  • In which of these positions will earth move the fastest
    7·1 answer
  • John pushes a 10 pound box 5 feet. How much work is done?
    14·1 answer
  • Of the following metals, which is the MOST reactive? A. Li B. Be C. Na D. Mg
    5·1 answer
  • Please help please help
    12·1 answer
  • An electron in the beam of a cathod-ray tube is accelerated by a potential difference of 2.12 kV . Then it passes through a regi
    9·1 answer
  • An object with more mass has more kinetic energy than an object with less mass, if both objects are moving ____.
    10·2 answers
  • The tidal lung volume of human breathing, representing the amount of air inhaled and exhaled in a normal breath, is 500 cm3. (As
    8·1 answer
  • Good morning! Can someone please answer this, ill give you brainliest and you will earn 50 points.
    14·2 answers
  • Why a hole at the bottom of a ship is more dangerous than the one that is near the surface?​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!