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jasenka [17]
3 years ago
10

Name six kinds of simple machines.

Physics
2 answers:
Gnom [1K]3 years ago
8 0

Answer:

the wheel and axle, the lever, the inclined plane, the pulley, the screw, and the wedge

Explanation:

Nutka1998 [239]3 years ago
3 0
The wheel, Axel, Lever, Inclined Pane, pulley, screw, and wedge!
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How much work does it take to move a 50 μC charge<br> against a 12 V potential difference?
lukranit [14]
<span>work =V*Q =12*50*10^-6

The total work done will be equal to 

work = V.Q

which means 

w= 12 . 50.10^-6
Hence,
w= 0.0006 J</span>
8 0
2 years ago
A light wave traveling through medium 1 strikes a boundary with medium 2 at at a 45 degree angle. the light then enters the seco
Alona [7]

Here light ray strikes to interface at an angle of 45 degree and then refracts into other medium such that it will bend towards boundary.

So here the angle of incidence will be less than the angle of refraction as light moves towards the boundary after refraction which mean it will bend away from the normal

here it can be said that medium 2 will be rarer then medium 1

So here the possible options are

1. Water  

Air

2. Diamond  

Air

So in above two options medium 1 is denser and medium 2 is rarer

8 0
2 years ago
Marcus tells Sabrina that for the last few months, he has not been able to detect moderate heat or cold with his fingertips. Whi
hram777 [196]

Answer: The free ending nerves.

Explanation:

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Like touching something with a given texture, feeling pain, or noticing changes in temperature.

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So Marcus may have the free nerve endings damaged.

4 0
3 years ago
When a photon collides with an electron and is deflected, the photon’s ____ decreases.
masha68 [24]

Answer:

2. Wavelength

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7 0
3 years ago
Read 2 more answers
Based on observations, the speed of a jogger can be approximated by the relation v 5 7.5(1 2 0.04x) 0.3, where v and x are expre
castortr0y [4]

Answer:

solution:

to find the speed of a jogger use the following relation:  

V

=

d

x

/d

t

=

7.5

×m

i

/

h

r

...........................(

1

)  

in Above equation in x and t. Separating the variables and integrating,

∫

d

x

/7.5

×=

∫

d

t

+

C

or

−

4.7619  

=

t

+

C

Here C =constant of integration.   

x

=

0  at  t

=

0

, we get:  C

=

−

4.7619

now we have the relation to find the position and time for the jogger as:

−

4.7619  =

t

−

4.7619

.

.

.

.

.

.

.

.

.

(

2

)

Here

x  is measured in miles and  t  in hours.

(a) To find the distance the jogger has run in 1 hr, we set t=1 in equation (2),    

     to get:

      = −

4.7619  

      =  

1

−

4.7619

      = −

3.7619

  or  x

=

7.15

m

i

l

e

s

(b) To find the jogger's acceleration in   m

i

l

/

differentiate  

     equation (1) with respect to time.

     we have to eliminate x from the equation (1) using equation (2).  

     Eliminating x we get:

     v

=

7.5×

     Now differentiating above equation w.r.t time we get:

      a

=

d

v/

d

t

       =

−

0.675

/

      At  

      t

=

0

      the joggers acceleration is :

       a

=

−

0.675

m

i

l

/

        =

−

4.34

×

f

t

/  

(c)  required time for the jogger to run 6 miles is obtained by setting  

        x

=

6  in equation (2).  We get:

        −

4.7619

(

1

−

(

0.04

×

6  )

)^

7

/

10=

t

−

4.7619

         or

         t

=

0.832

h

r

s

6 0
3 years ago
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