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4 years ago

Why do you think Kool Aid comes in packets that has a very finely ground powder (finely ground means very small particles)?

1 answer:

5 0

Kool-Aid is usually sold in powder form, in either packets or small tubs. The actual beverage is prepared by mixing the powder with sugar (the packets of powder are usually, though not always, unsweetened) and water, typically by the pitcherful. The drink is usually either served with ice or refrigerated and served chilled. Additionally, there are some sugar-free varieties.

Dissolving pretty well anything which is not itself going to boil or evaporate will increase the boiling point. So sugar, salt, Kool-Aid, all will elevate the boiling point of water.

Elevation of boiling point of a solution is one of several “colligative properties”, as we were told to call them in O-level chemistry. These are properties of a solution that change according to how many particles of solute are dissolved.

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A student sits on a pivoted stool while holding a pair of weights. The stool is free to rotate about a vertical axis with neglig

Novay_Z [31]

Answer:

a) 4.99 rad/sec b) 6.24 rad/sec c) 7.03 J

Explanation:

a) If the student completes one turn in 1.26 sec, this is called the period of the movement.

If we take into account that the angle rotated during one turn, is 2π rads, by definition of angular velocity, we can get this value as follows:

ω = Δθ / Δt = 2*π rad / 1.26 seg = 4.99 rad/sec.

b) As no external torques are acting on the system, the total angular momentum must be conserved, so we can write the following equation:

Li = Lf ⇒ I₁ * ω₁ = I₂* ω₂

So, we can solve for ω₂, as follows:

ω₂ = (I₁ * ω₁) / I₂ = 6.24 rad/sec

c) Appying the work-energy theorem, we know that the work done by the student, must be equal to the change in the kinetic energy, which in this case is only rotational, so we can write:

W = 1/2 I₂* ω₂² - 1/2 I₁ ω₁²

W =1/2 ((2.25 kg.m² * (6.24)²) (rad/sec)² - (1.8 kg.m²* (4.99)²) (rad/sec)²)

W = 7.03 J

4 0

3 years ago

Mrs. Garcia's earth science class conducted an experiment on how Earth absorbed solar radiation. They placed four different shee

SIZIF [17.4K]

Warmest-Black. Absorbs the most heat.

Coolest-white. Doesn't absorb heat.

8 0

4 years ago

Read 2 more answers

An object in motion stays in motion, in a _______________________, unless acted on by an external _____________________________

Nat2105 [25]

Answer:

See the explanation below.

Explanation:

in a <u>motion (or constant speed)</u> unless acted on by an external <u>unbalanced </u>force.

This explanation corresponds to newton's second law which tells us that the sum of the forces acting on a body is equal to the product of mass by acceleration, if the object moves with constant speed it is because on this act forces that do not decrease to increase its speed.

5 0

4 years ago

A ball is dropped from a building of height h. Derive an equation for its velocity just before it hits the ground. Assume no air

swat32

Answer:

The final velocity of the ball just hits the ground is $\sqrt{2gh}$ .

Explanation:

A ball is dropped from the height h. As the ball is dropped means there is no initial velocity given to the ball.

GIVEN:

The distance traveled by the ball is equal to h.

Initial velocity of the ball is zero.

Concept:

Two type of force comes into play in dropping of ball.

1. Gravitational force

Due to gravitational force ball forced to fall downward towards the surface.

2. Air resistance

Air develops drag force on the ball in opposite direction of the gravitational force.

Assumption:

There is no air resistance in falling of ball. So, there will be no drag force on the ball.

Calculation:

It is given that a ball is dropped from a building of height h.

The Newton’s equations of motion are as follows:

$V^{2}-u^{2}=2as$

$s=ut+\frac{1}{2}at^{2}$

$v=u+at$

STEP 1

Newton’s equation of motion is expressed as follows:

$V^{2}-u^{2}=2as$

Here, V is final velocity of the ball just before the ball hits the ground, a is acceleration due to gravity, u is the initial velocity of the ball and s is the distance traveled by the ball.

Here, initial velocity is zero. So, u = 0 m/s.

Vertical distance traveled by the ball is h. So, s= h.

Only gravitational force is responsible for motion as well as for acceleration. Thus, the acceleration due to gravity acts on the ball. Acceleration due to gravity is denoted by small g.

Acceleration due to gravity is constant for different planate. The acceleration due to gravity for the earth is 9.8 m/s². Here, no planet is defined. So the acceleration due to gravity is a = g.

Substitute 0 for m/s, g for a and h for s in above equation as follows:

$V^{2}-u^{2}=2as$

$V^{2}-(0)^{2}=2gh$