Answer:
Molality = <u>10.300 m</u>
<u>Molarity = 6.5970 M</u>
<u>mole fraction = </u>0.156549
Explanation:
39.0 % = ethylene glycol
61.0 % = water
imagine the total mass = 100g
39.0% ethylene glycol = 39g
61.0 % water = 61g
1) Molality = number of moles / mass of solvent (kg)
Molar mass of ethylene glycol = 62.07g/mole
mole = 39g / 62.07g/mole = 0.6283 moles
Molality = moles / mass of solvent = 0.6283 moles / 0.061kg = <u>10.300 m</u>
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<u>2) Molarity</u> = number of moles / volume of solution
Since we know the density of the solution = 1.05g /ml
⇒ volume = 100g / 1.05g /mL = 95.24 mL = 0.09524 L
Molarity = 0.6283 moles / 0.09524 L = <u>6.5970 M</u>
3) Mole fraction
moles water = 61g / 18.02g/mole = 3.38513 moles
Total number of moles = moles of ethylene glycol + moles of water = 0.6283 + 3.38513 = 4.0134276 moles
Mole fraction = 0.6283/ 4.0134276 = 0.156549
