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myrzilka [38]
3 years ago
13

A student is using a coffee-cup calorimeter to determine the enthalpy change of the endothermic reaction of two aqueous solution

s. After both solutions are added to the cup, the student neglects to put the lid on the cup. This would cause the magnitude of the calculated ΔH° value to be: the answer is: too small, since the solution will absorb heat from the room. But why? Wouldn't depend on if the reaction releases or absorbs heat. Wouldn't it be too large because heat escapes the cup? I'm so confused
Chemistry
1 answer:
Liula [17]3 years ago
8 0

Answer:

See the answer below

Explanation:

<em>First, it should be understood that an endothermic reaction is one that absorbs energy in the form of heat from the surrounding.</em> The products of endothermic reactions usually have higher energy than their reactants. Hence, the ΔH° which is referred to as the enthalpy change is usually positive.

<u>Forgetting to cover the coffee-cup calorimeter means some of the heat energy absorbed by the reactants would be exchanged back to the surroundings - a loss.</u> It also means that the enthalpy change would be smaller compared to if the cup had been covered because some of the heat has been lost to the surrounding.

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densk [106]
4)<span>1.24⋅<span>1024</span></span><span> formula units

</span>1 mole Na<span> (sodium)</span>
6 0
3 years ago
A 60g sample of tetraethyl lead, a gasoline additive, is found to contain 38.43g lead, 17.83g carbon and 3.74g hydrogen. Determi
anastassius [24]

Answer:

Empirical formula (which matches the molecular formula) is = PbC₈H₂₀

Explanation:

Our sample: 60 g of tetraethyl lead

In order to determine the compound empirical formula we need the centesimal composition:

(Mass of element / Total mass) . 100 =

(38.43 g lead / 60g ) . 100 = 64.05%

(17.83 g C / 60g) . 100 = 29.72%

(3.74 g H / 60g) . 100 = 6.23 %

These % are the mass of the elements in 100 g of compound. Let's find out the moles of them:

64.05 g / 207.2 g/mol = 0.309 moles

29.72 g / 12 g/mol = 2.48 moles

6.23 g/ 1 g/mol = 6.23 moles

Next, we divide the moles, by the lowest value of them (0.309)

0.309 / 0.309 = 1 mol Pb

2.48 / 0.309 = 8 mol C

6.23 / 0.309 = 20 mol H

There, we have our formula PbC₈H₂₀

6 0
3 years ago
How many molecules OF2 would have a mass of .132 g
BlackZzzverrR [31]
<h3>Answer:</h3>

1.47 × 10²¹ molecules OF₂

<h3>General Formulas and Concepts: </h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation: </h3>

<u>Step 1: Define</u>

0.132 g OF₂

<u>Step 2: Identify Conversions</u>

Avogadro's Number

Molar Mass of O - 16.00 g/mol

Molar Mass of F - 19.00 g/mol

Molar Mass of OF₂ - 16.00 + 2(19.00) = 54.00 g/mol

<u>Step 3: Convert</u>

  1. Set up:                               \displaystyle 0.132 \ g \ OF_2(\frac{1 \ mol \ OF_2}{54.00 \ g \ OF_2})(\frac{6.022 \cdot 10^{23} \ molecules \ OF_2}{1 \ mol \ OF_2})
  2. Divide/Multiply:                                                                                               \displaystyle 1.47204 \cdot 10^{21} \ molecules \ OF_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.47204 × 10²¹ molecules OF₂ ≈ 1.47 × 10²¹ molecules OF₂

3 0
3 years ago
The density of a material is a/n
Darya [45]

Answer:

Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has high density.

Explanation:

7 0
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Answer:

V = 102.0 ml

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density = m / V

= 91.0 / 102.0

= 0.89215 g/ml

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2 years ago
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