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Naya [18.7K]
3 years ago
14

Construction crews sometimes use this reaction for welding underwater structures:

Chemistry
2 answers:
STALIN [3.7K]3 years ago
8 0
It's 5.00 I just took it 
Tanzania [10]3 years ago
6 0

Answer:

5 moles of iron (Fe) would be produced if 2.50 mol of Fe₂O₃ reacted.

Explanation:

The rule of three or is a way of solving problems of proportionality between three known values and an unknown value, establishing a relationship of proportionality between all of them. That is, what is intended with it is to find the fourth term of a proportion knowing the other three. Remember that proportionality is a constant relationship or ratio between different magnitudes.

If the relationship between the magnitudes is direct, that is, when one magnitude increases, so does the other (or when one magnitude decreases, so does the other) , the direct rule of three must be applied. To solve a direct rule of three, the following formula must be followed:

a ⇒ b

c ⇒ x

So:

x=\frac{b*c}{a}

The rule of three in this case is applied as follows: if 1 mole of Fe₂O₃ produces 2 moles of Fe by stoichiometry, 2.5 moles of Fe₂O₃ how many moles of Fe will it produce?

moles of Fe=\frac{2moles of Fe*2.5 moles of Fe_{2} O_{3} }{1 moles of Fe_{2} O_{3} }

moles of Fe= 5

<u><em> 5 moles of iron (Fe) would be produced if 2.50 mol of Fe₂O₃ reacted.</em></u>

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Which will most likely result if the levels of dissolved oxygen decrease in a body of water?
Lerok [7]

Answer:

B) Native fish species will begin to decrease in population size.

Hope it helps:D

5 0
2 years ago
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ASAP
Nadya [2.5K]

Answer:

12 %

Explanation:

Produces 15 J of work for input 125 J

15/125 * 100% = 12%

5 0
1 year ago
Water can be formed in the following reaction:
andreev551 [17]

Answer is: 10 moles of water will be produced.

Balanced chemical reaction of formation of water:

2H₂ + O₂ → 2H₂O.

n(H₂) = 10 mol; amount of hydrogen gas.

From balanced chemical reaction: n(H₂) : n(H₂O) = 2 : 2 (1 : 1).

n(H₂O) = n(H₂).

n(H₂O) = 10 mol; amount of water.

6 0
3 years ago
Determine the value of the equilibrium constant, KgoalKgoalK_goal, for the reaction CO2(g)⇌C(s)+O2(g)CO2(g)⇌C(s)+O2(g), Kgoal=?
NISA [10]

Answer:

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

Explanation:

CO_2(g)\rightleftharpoons C(s)+O_2(g)

K_{goal}=?

K_{goal}=\frac{[C][O_2]}{[CO_2]}

2CO_2(g)+2H_2O(l)\rightleftharpoons CH_3COOH(l)+2O_2(g)..[1]

K_1=\frac{[CH_3COOH][O_2]^2}{[CO_2]^2[H_2O]^2}

2H_2(g)+O2(g)\rightleftharpoons 2H_2O(l)..[2]

K_2=\frac{[H_2O]^2}{[H_2]^2[O_2]}

CH_3COOH(l)\rightleftharpoons 2C(s)+2H_2(g)+O_2(g)..[3]

K_3=\frac{[C]^2[H_2]^2[O_2]}{[CH_3COOH]}

[1] +  [2] + [3]

2CO_2(g)\rightleftharpoons 2C(s)+2O_2(g)

 ( on adding the equilibrium constant will get multiplied with each other)

K=K_1\times K_2\times K_3

K=5.40\times 10^{-16}\times 1.06\times 10^{10}\times 2.68\times 10^{-9}

K=1.53\times 10^{-14}

K=\frac{[C]^2[O_2]^2}{[CO_2]^2}

On comparing the K and K_{goal}:

K^2=K_{goal}

K_{goal}=\sqrt{K}=\sqrt{1.53\times 10^{-14}}=1.24\times 10^{-7}

The value of the equilibrium constant for reaction asked is 1.24\times 10^{-7}.

4 0
3 years ago
Write the name of the main gases in the air​
Delicious77 [7]

Answer:

Nitrogen

Oxygen

Argon

Carbon Dioxide

Methane

Ozone

Explanation:

N₂ accounts for 78% of the atmosphere.

O₂ accounts for 21% of the atmosphere.

Ar accounts for 0.9% of the atmosphere.

CO₂, CH₄, and O₃ only take up 0.1% of the atmosphere.

3 0
3 years ago
Read 2 more answers
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