Answer:
the amplitude of the subsequent oscillations is 0.11 m
the period of the subsequent oscillations is 1.94 s
Explanation:
given Information:
the mass of air-track glider, = 750 g = 0.75 kg
spring constant, k = 13.0 N/m
the mass of glider, = 200 g = 0.2 kg
the speed of glider, = 170 cm/s = 1.7 m/s
the amplitude of the subsequent oscillations is A = 0.11 m
according to mechanical enery equation, we have
where
A is the amplitude and is the final speed.
to find , we can use momentum conservation lwa, where the initial momentum is equal to the final momentum.
= 0, thus
(0.75+0.2) = (0.75)(0)+(0.2)(1.7)
0.95 = 0.34
= 0.36 m/s
Now we can calculate the amplitude
A = 0.11 m
the period of the subsequent oscillations is T = 1.94 s
the equation for period is
T = 2π
T = 2π
T = 1.94 s