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ololo11 [35]
2 years ago
13

The potential at location A is 570 V. A positively charged particle is released there from rest and arrives at location B with a

speed vB. The potential at location C is 1180 V, and when released from rest from this spot, the particle arrives at B with twice the speed it previously had, or 2 vB. Find the potential at B.
Physics
1 answer:
KIM [24]2 years ago
3 0

Answer:

Potential at B, VB = 367 V

Explanation:

The explanation is found in the attachment below

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Answer:

Case A

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F = \eta A \dfrac{dv}{dx}

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F = \eta \times 10^{-6}\times 20\times 10^{-3}

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from the above force calculation

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3 years ago
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3 years ago
William Gilbert used a terella in an attempt to explain _____.
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To demonstrate the tremendous acceleration of a top fuel dragracer, you attempt to run your car into the back of a dragster that
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Answer:

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3 years ago
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