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Svet_ta [14]
3 years ago
10

An 80.0-gram sample of water at 10.0°C absorbs 1680 Joules of heat energy. What is the final temperature of the water? a 50.0°C

b 15.0°C c 5.00°C d 4.00°C
Chemistry
1 answer:
ICE Princess25 [194]3 years ago
7 0

Answer:

b)15.0°C

Explanation:

Specific Heat of Water=4.2 J/g°C

This means, that 1 g of Water will take 4.2 J of energy to increase its temperature by 1°C.

∴80 g Water will take 80×4.2 J of energy to increase its temperature by 1°C.

80×4.2 J=336 J

Total Energy Provided=1680 J

The temperature increase=\frac{\textrm{Total energy required}}{\textrm{energy required to increase temperature by one degree}}

Temperature increase=\frac{1680}{336}

=5°C

Initial Temperature =10°C

Final Temperature=Initial + Increase in Temperature

=10+5=15°C

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Homelearning
kirill115 [55]

Answer:

Number of moles of Fe = 10 mol

Number of moles of CO₂ = 15 mol

Explanation:

Given data:

Number of moles of iron oxide = 5 mol

Number of moles of carbon monoxide = 25 mol

Number of moles of product = ?

Solution:

Fe₂O₃ + 3CO   →  2Fe + 3CO₂

Now we will compare the moles of reactant with product.

                  Fe₂O₃        :         Fe

                     1             :          2

                    5             :         2×5 = 10 mol

                Fe₂O₃        :         CO₂

                     1             :          3

                    5             :         3×5 = 15 mol

                  CO           :         Fe

                     3             :          2

                    25             :         2/3×25 = 16.7 mol

                  CO            :         CO₂

                     3             :          3

                    25             :         25

Less number of moles of Fe and CO₂ are formed by iron oxide thus it will act as limiting reactant while CO is inn excess.

                 

4 0
2 years ago
Electroplating is a way to coat a complex metal object with a very thin (and hence inexpensive) layer of a precious metal, such
8_murik_8 [283]

Answer:

0.0164 g

Explanation:

Let's consider the reduction of silver (I) to silver that occurs in the cathode during the electroplating.

Ag⁺(aq) + 1 e⁻ → Ag(s)

We can establish the following relations.

  • 1 A = 1 C/s
  • The charge of 1 mole of electrons is 96,468 C (Faraday's constant)
  • 1 mole of Ag(s) is deposited when 1 mole of electrons circulate.
  • The molar mass of silver is 107.87 g/mol

The mass of silver deposited when a current of 0.770 A circulates during 19.0 seconds is:

19.0s \times \frac{0.770c}{s} \times \frac{1mole^{-} }{96,468C} \times \frac{1molAg}{1mole^{-}} \times \frac{107.87g}{1molAg} = 0.0164 g

5 0
2 years ago
If the partial pressure of oxygen outside of a cell is 100 mmHg and the partial pressure of oxygen inside of a cell is 25 mmHg,
mrs_skeptik [129]

" There will be a net movement of oxygen from outside the cell to inside the cell " Statement is True.

Explanation:

The partial pressure for oxygen in alveoli is greater under normal circumstances, and oxygen moves neatly into the blood. In addition, the partial carbon dioxide pressure throughout the blood usually is higher, such that carbon dioxide migrate clearly into the alveoli.

The few common molecules which can traverse the cell membrane by absorption (or diffusion of a sort recognized as osmosis) are water, carbon dioxide and oxygen. Metabolism is typically oxygen-needed, which is lowest in the cell within the animal and plant, so that net oxygen flows to the cell.

3 0
3 years ago
What is the formula for titanium (I) dichromate?
MaRussiya [10]
The answer is TI(Cr207)2
8 0
2 years ago
Plants that have nigrogen fixing bacteria in their roots are called​
iragen [17]

Plants that have nigrogen fixing bacteria in their roots are called​

legumes.

8 0
2 years ago
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