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3 years ago

Which change would cause the largest increase in a mountain climber’s gravitational potential energy?

Physics

1 answer:

love history [14]3 years ago

4 0

Increase in height can cause climber's gravitational potential energy greater than any other mean

Hope this helps!

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A 0.25 kg ball is suspended from a light 0.65 m string as shown. The string makes an angle of 31° with the vertical. Let U = 0 w

steposvetlana [31]

Explanation:

a) The height of the ball h with respect to the reference line is

$h = L - L\cos{31°} = L(1 - \cos{31°})$

so its initial gravitational potential energy $U_0$ is

$U = mgh = mgL(1 - \cos{31°})$

$\:\:\:\:\:=(0.25\:\text{kg})(9.8\:\text{m/s}^2)(0.65\:\text{m})(1 - \cos{31})$

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b) To find the speed of the ball at the reference point, let's use the conservation law of energy:

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$mgL(1 - \cos{31°}) = \frac{1}{2}mv^2$

Note that the mass gets cancelled out and then we solve for the velocity v as

$v = \sqrt{2gL(1 - \cos{31°})}$

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When you push on an object such as a wrench, a steel pry bar, or even the outer edge of a door, you produce a torque equal to th

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Since youc oncetrate all your force directly towards the moment arm it means that you push it at an angle of your force is directed to the left or the right and I bet that it must be 90 degrees to the bar. Obviuosly, if you are about to push it you will do it straight up but not in a zig zag way. In other words, it should be perpendicular to the arm because the torque can be produced only if force is applied at a constant index (90).
Hope that helps! Regards.

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