Answer:
The speed of James is 0.776 m/s
Explanation:
Step 1: Data given
mass of James = 95.0 kg
mass of Ramon = 67.0 kg
We consider James and Ramon and the rope to a single system. This means that the net external forces on the system = 0
.The momentum = 0, so the sum of the momentum of each part must be 0 in total.
Step 2: Calculate the speed of James
m(james) *v(James) = m(Ramon) * v(Ramon)
with m(James) = the mass of James = 95.0 kg
with v(James) = speed of James = TO BE DETERMINED
with m(Ramon) = mass of Ramon = 67.0 kg
with v(Ramon) = speed of Ramon = 1.10 m/s
v(James) = (m(Ramon) * v(Ramon))/ m(james)
v(James) = (67.0 kg* 1.10 m/s) / 95.0 kg
v(James) = 0.776 m/s
The speed of James is 0.776 m/s
Option B makes best sense, correct me if i’m wrong
Answer:
x = 4,138 m
Explanation:
For this exercise, let's use the rotational equilibrium equation.
Let's fix our frame of reference on the left side of the pivot, the positive direction for anti-clockwise rotation
∑ τ = 0
n₁ 0 - W L / 2 + n₂ 4 - W_woman x = 0
x = (- W L / 2 + 4n2) / W_woman
Let's reduce the magnitudes to the SI System
M = 6 lbs (1 kg / 2.2 lb) = 2.72 kg
M_woman = 130 lbs = 59.09 kg
Let's write the transnational equilibrium equation
n₁ + n₂ - W - W_woman = 0
n₁ + n₂ = W + W_woman
n₁ + n₂ = (2.72 + 59.09) 9.8
At the point where the system begins to rotate, pivot 1 has no force on it, so its relation must be zero (n₁ = 0)
n₂ = 605,738 N
Let's calculate
x = (-2.72 9.8 6/2 + 4 605.738) / 59.09 9.8
x = 4,138 m
Star 1 - 4 hours right ascension
Star 2 - 3 hours right ascension
Subtracting hours right ascension
4 hours right ascension - 3 hours right ascension = 1 hours right ascension.
Thus,
star 1 will rise 1 hour before star 2
