Answer:
0.00288 L = 2.88 mL.
Explanation:
- To calculate the no. of moles of a gas, we can use the general law of ideal gas: <em>PV = nRT.</em>
where, P is the pressure of the gas in atm.
V is the volume of the gas in L.
n is the no. of moles of the gas in mol.
R is the general gas constant.
T is the temperature of the gas in K.
- If n is constant, and have two different values of (P, V and T):
<em>P₁V₁T₂ = P₂V₂T₁</em>
<em></em>
P₁ = 1.0 atm, V₁ = 1.5 L, T₁ = 37°C + 273 = 310 K.
P₂ = 500.0 atm, V₂ = ??? L, T₂ = 25°C + 273 = 298 K.
<em>∴ V₂ = P₁V₁T₂/P₂T₁</em> = (1.0 atm)(1.5 L)(298 K)/(500.0 atm)(310 L) = <em>0.00288 L = 2.88 mL.</em>
