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blondinia [14]
3 years ago
8

What part of an atom is detected by stm?

Chemistry
1 answer:
Digiron [165]3 years ago
7 0
The Electrons stm is Scanning tunnelling microscope.It is used into the neno technology.In it the neno object looks very large so that the perticular work with them to be <span>taken from them and they can be used to make human life more beautiful and comfertable.</span>
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Identify and calculate the number of representative particles in 2.15 moles of gold.<br>​
LekaFEV [45]

Answer:

1.29 * 10^{24} particles of gold

Explanation:

To convert the number of moles of any substance, in this case gold, you need Avogadro's number.

Avogadro's number is always 6.022 × 10^{23}

2.15 moles Au × \frac{6.022*10^{23} particles}{1 mole Au} = 1.29 * 10^{24} particles of gold

5 0
3 years ago
Consider the following reaction:C2H4(g) + F2(g) -----------&gt; C2H4F2(g) Delta H = -549 kJEstimate the carbon-fluorine bond ene
frutty [35]

Answer:

Bond energy of carbon-fluorine bond is 485 kJ/mol

Explanation:

Enthalpy change for a reaction,  is given as:

\Delta H_{rxn}=\sum [n_{i}\times (E_{bond})_{i}]-\sum [n_{j}\times (E_{bond})_{j}]

Where (E_{bond})_{i}  and (E_{bond})_{j} represents average bond energy in breaking "i" th bond and forming "j" th bond respectively.n_{i} and n_{j} are number of moles of bond break and form respectively.

In this reaction, one mol of C=C, four moles of C-H and one mol of F-F bonds are broken. One mol of C-C bond, four moles of C-H bonds and two moles of C-F bonds are formed

So, -549kJ=(1mol\times 614kJ/mo)+(4mol\times E_{C-H})+(1mol\times 154kJ/mol)-(1mol\times 347kJ/mol)-(4mol\times E_{C-H})-(2mol\times E_{C-F})

or, -549kJ=(1mol\times 614kJ/mo)+(1mol\times 154kJ/mol)-(1mol\times 347kJ/mol)-(2mol\times E_{C-F})

or, E_{C-F}=485kJ/mol

So bond energy of carbon-fluorine bond is 485 kJ/mol

8 0
3 years ago
The solubility of copper(i) chloride is 3.91 mg per 100.0 ml of solution. calculate ksp for cucl (cucl=99.00 g mol-1).
garri49 [273]
Convert  Mg  to  grams
1g =1000mg  what  about  3.91  Mg
=  3.91mg  x  1g/1000mg=  3.91  x10^-3 g
moles= mass/molar mass
that  is  3.91  x10^-3g  /99 g/mol=3.95 x10^-5moles
concentration=   moles  /  vol   in  liters

that  is  3.95  x10^-5/100  x1000=  3.94  x10^-4M

equation for  dissociation  of  CUCl=   CUCl---->  CU^+   +Cl^-

Ksp=(CU+)(CI-)
that  is  (3.95  x10^-4)(3.95  x10^-4)
Ksp=  1.56  x10^-7
3 0
3 years ago
Read 2 more answers
The critical point of carbon dioxide is 304 k and 73 atm. under which conditions is carbon dioxide a liquid? i. 303 k and 73 atm
Sergeeva-Olga [200]
Answer is: a) I only.
Above critical temperature of CO₂, a gas cannot be liquefied no matter how much pressure is applied. Temperature and pressure above its critical point is called supercritical fluid and this is <span>intermediate between gaseous and liquid states.</span>
7 0
3 years ago
How many calories is required to change the temperature of 2.18g of water from 15.3°C to 69.5°C. The specific heat of liquid wat
lozanna [386]

The number  of calories that are  required  to change the temperature  of 2.18 g of water from 15.3 c to 69.5 c is  <u>118.16 cal</u>


    <u><em> calculation</em></u>

  •    Heat in calories  = MCΔ T where,
  • M(mass)= 2.18 g
  • C(specific heat capacity)= 1.00 cal/g/c
  • ΔT( change in temperature)= 69.5- 15.3 =54.2 c

 heat is therefore= 2.18 g x 1.00 cal/g/c  x 54.2 c=118.16  cal

7 0
3 years ago
Read 2 more answers
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