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krok68 [10]
2 years ago
13

What is nylon?answer​

Physics
2 answers:
Igoryamba2 years ago
8 0
A tough, lightweight, elastic synthetic polymer with a protein-like chemical structure, able to be produced as filaments, sheets, or molded objects.
Triss [41]2 years ago
7 0

Answer:

Nylon is a generic designation for a family of synthetic polymers composed of polyamides.

Explanation:

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PLEASE HELP QUICKLY THANKS
Dmitriy789 [7]

Answer: the answer is d

Explanation:

7 0
3 years ago
What does this circle graph tell you about water on Earth? (2 points)
vekshin1

Answer:

ocean covers 71 percent of the earth

8 0
3 years ago
A spring hangs at rest from a support. If you suspend a 0.46 kg mass from the spring it elongates 0.79m.
Fudgin [204]

a. The restoring force in the spring has magnitude

F[spring] = k (0.79 m)

which counters the weight of the mass,

F[weight] = (0.46 kg) g = 4.508 N

so that by Newton's second law,

F[spring] - F[weight] = 0   ⇒   k = (4.508 N) / (0.79 m) ≈ 5.7 N/m

b. Using the same equation as before, we now have

F[weight] = (0.75 kg) g = 7.35 N

so that

(5.7 N/m) x - 7.35 N = 0   ⇒   x = (7.35 N) / (5.7 N/m) ≈ 1.3 m

4 0
2 years ago
A spring with spring constant 33N/m is attached to the ceiling, and a 4.8-cm-diameter, 1.5kg metal cylinder is attached to its l
mylen [45]

Answer:

0.423m

Explanation:

Conversion to metric unit

d = 4.8 cm = 0.048m

Let water density be \who_w = 1000 kg/m^3

Let gravitational acceleration g = 9.8 m/s2

Let x (m) be the length that the spring is stretched in equilibrium, x is also the length of the cylinder that is submerged in water since originally at a non-stretching position, the cylinder barely touches the water surface.

Now that the system is in equilibrium, the spring force and buoyancy force must equal to the gravity force of the cylinder. We have the following force equation:

F_s + F_b = W

Where F_s = kxN is the spring force, F_b = W_w = m_wg = \rho_w V_s g is the buoyancy force, which equals to the weight W_w of the water displaced by the submerged portion of the cylinder, which is the product of water density \rho_w, submerged volume V_s and gravitational constant g. W = mg is the weight of the metal cylinder.

kx + \rho_w V_s g = mg

The submerged volume would be the product of cross-section area and the submerged length x

V_s = Ax = \pi(d/2)^2x

Plug that into our force equation and we have

kx + \rho_w \pi(d/2)^2x g = mg

x(k + \rho_w g \pi d^2/4) = mg

x = \frac{m}{(k/g) + (\rho_w\pi d^2/4)} = \frac{1.5}{(33/9.8) + (100*\pi * 0.048^2/4)} = 0.423 m

6 0
2 years ago
If the out come of a 1.0-kg ball moving at 3.0 m/s is 4.5 kinetic energy what would the kinetic energy be if the mass and speed
Flauer [41]

Answer: KE = 36 J

Explanation: Solution:

KE = 1/2 mv²

= 1/2 ( 2 kg)(6 m/s)²

= 36 J

7 0
3 years ago
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