It will be a funny fraction = 0.5714285714
Answer:
A. 
Step-by-step explanation:
We need to determine whether the polynomial
can be factored into perfect squares. If so, factor the polynomial. Otherwise, select that it cannot be factored into a perfect square.









Hence choice A.
is correct.
Answer:
(d) f(x) = -x²
Step-by-step explanation:
For the vertex of the quadratic function to be at the origin, both the x-term and the constant must be zero. That is, the function must be of the form ...
f(x) = a(x -h)² +k . . . . . . . . . . vertex form; vertex at (h, k)
f(x) = a(x -0)² +0 = ax² . . . . . vertex at the origin, (h, k) = (0, 0)
Of the offered answer choices, the only one with a vertex at the origin is ...
f(x) = -x² . . . . . a=-1