Answer:
v = 17.71 m / s
Explanation:
We can work this exercise with the kinematics equations. In general the body is released so that its initial velocity is zero, the acceleration of the acceleration of gravity
v² = v₀² - 2 g (y -y₀)
v² = 0 - 2g (y -y₀)
when it hits the stone the height is zero and part of the height of the seagull I
v² = 2g y₀
v = Ra (2g i)
let's calculate
v =√ (2 9.8 16)
v = 17.71 m / s
Answer:
25 m/s
Explanation:
Centripetal acceleration is the square of the tangential velocity divided by the radius.
a = v² / r
15.625 m/s² = v² / (40 m)
v² = 625 m²/s²
v = 25 m/s
The speed of the car is 25 m/s.
Answer:
After one half of the battery's useful life.
Explanation:
Batteries of the emergency locator transmitter (ELT) must be replaced or recharged after one half of the battery's useful life because if it is exposed to the high temperature for a long period of time such as the air plane parked in the sun will result in the deterioration of battery which may makes the transmitter out of order before the expiry date of the battery. So it will be safe to do that after the use of one half of the battery's life.
It’s d all the other answer would not be a chemical property
Answer:
109.66km
Explanation:
Velocity is defined as the change in displacement of a body with respect to time.
Velocity = displacement/Time
Displacement = velocity * time
A truck is traveling due north at 75 km/hr approaching a crossroad and perpendicular road a police car is traveling west toward the intersection at 80 km/hr, then the resultant velocity is gotten using the pythagoras theorem since they are both perpendicular to each other.
v² = 75²+80²
v² = 5625+6400
v² = 12,025
v = √12,025
v = 109.66km/hr
If both vechicles reaches cross road in exactly one hour, the displacement of the truck with respect to the police car = 109.66km/hr * 1 hour
Displacement of the truck with respect to the police car = 109.66km
