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Musya8 [376]
3 years ago
10

Why is it possible for a gas to take the shape of its container?

Physics
2 answers:
Sedaia [141]3 years ago
8 0
I believe the answer is A

Gelneren [198K]3 years ago
8 0
The answer is a , hope that helped
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Explain how evaporation cools a liquid​
MAVERICK [17]

When evaporation occurs liquid absorbs heat from the surroundings to get converted to its vapour form as a result, there is an overall decrease in the heat leading to cooling of the liquid.

Hope that this was helpful :)

8 0
3 years ago
Does moon have a dense atmosphere
nata0808 [166]

Answer:

No

Explanation:

Moon does not have any atmosphere.

Please mark as brainliest

3 0
3 years ago
Ammonia and _________ are waste products of animal cells. A. oxygen B. urine C. hydrogen D. carbon dioxide
pickupchik [31]

B or D, one of these are the correct answer

7 0
3 years ago
The mean free path of a helium atom in helium gas at standard temperature and pressure is 0.2 um.What is the radius of the heliu
ivolga24 [154]

Answer: 0.10233nm

Explanation:

The mean free path \lambda   of an atom is given by the following formula:

\lambda=\frac{RT}{\sqrt{2} \pi d^{2}N_{A}P}    (1)

Where:

\lambda=0.2\mu m=0.2(10)^{-6}m

R=8.3145J/mol.K is the Universal gas constant

T=0\°C=273.115K is the absolute standard temperature

d is the diameter of the helium atom

N_{A}=6.0221(10)^{23}/mol is the Avogadro's number

P=1atm=101.3kPa=101.3(10)^{3}Pa=101.3(10)^{3}J/m^{3} absolute standard pressure

Knowing this, let's find d from (1), in order to find the radius r of the helium atom:

d=\sqrt{\frac{RT}{\sqrt{2}\pi\lambda N_{A}P}}    (2)

d=\sqrt{\frac{(8.3145J/mol.K)(273.115K)}{\sqrt{2}\pi(0.2(10)^{-6}m)(6.0221(10)^{23}/mol)(101.3(10)^{3}J/m^{3})}}    (3)

d=2.0467(10)^{-10}m    (4)

If the radius is half the diameter:

r=\frac{d}{2}  (5)

Then:

r=\frac{2.0467(10)^{-10}m}{2}  (6)

r=1.0233(10)^{-10}m  (7)

However, we were asked to find this radius in nanometers. Knowing 1nm=(10)^{-9}m:

r=1.0233(10)^{-10}m.\frac{1nm}{(10)^{-9}m}=0.10233nm  (8)

Finally:

r=0.10233nm This is the radius of the helium atom in nanometers.

5 0
3 years ago
Question 3 of 25 What is the period of a wave that has a frequency of 3 Hz?​
Katarina [22]

Answer:

use the formula

Explanation:

F = 1/ T

where F stands for frequency and T stands for period

sub in 3 Hz into frequency

3 = 1/T

0.333 = T

or in a fraction form

1/ 3

hope this helps

8 0
3 years ago
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